do I get exited with non-zero status in that pq code?

Question

#include<stdio.h>

int main(){
int i,jog,rod,placar[500],ponto=0,p,maxPonto=0,vencedor=0,rodCopia;

  scanf("%d %d",&jog,&rod);

  rodCopia = rod;

  for(i=1;i<=jog;i++){
          scanf("%d",&p);
          placar[i]+=p;
       if(i==jog && rod>0){
         rod-=1;
         i = 0;
       }

  }
       for(i=1;i<=rodCopia;i++){
         if(maxPonto < placar[i]){
           maxPonto = placar[i];
           vencedor = i;
         }

       }


     printf(vencedor); 
    return 0;
    }

Answer 1

The problem in its code is in the part where it starts from 1, the C language does not allow a vector to have a null zero position, so its first is, just as the second ignores the vector’s 0 position. To fix the problem start i do for as 0 and instead of letting "<=" make it smaller

Follow the tidy code

#include<stdio.h>

int main(){
int i,jog,rod,placar[500],ponto=0,p,maxPonto=0,vencedor=0,rodCopia;

  scanf("%d %d",&jog,&rod);

  rodCopia = rod;

  for(i=0;i<jog;i++){
    printf("Ok");
          scanf("%d",&p);
          placar[i]+=p;
       if(i==jog && rod>0){
         rod-=1;
         i = 0;
       }

  }
       for(i=0;i<rodCopia;i++){
         if(maxPonto < placar[i]){
           maxPonto = placar[i];
           vencedor = i;
         }

       }


     printf(vencedor); 
    return 0;
    }