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I have a file with strings I need at first filter for example only lines that has 5 characters And in a second moment filter only those that have at least 2 characters repeated together Example: display aazyx or zyaax but do not display azyxa And third filter lines q have at least one vowel.
That last one I know is possible, the other two I don’t know if it’s possible with sed. Thanks for your help and attention
3
I don’t know if I understand it very well, but suppose you have a text file in the following format:
txt file.
abcde
aabbc
kkkkk
ggggggggggggg
ccdde
We can filter as follows:
cat arquivo.txt | grep -x '.\{5,5\}' | grep -E '(.)\1{1}' | grep -E '[aeiouAEIOU]{1}'
Note 1: I think it would be better to use egrep instead of grep for regular expressions.
Obs 2: I am without time for the details, of a man grep to search for parameters.
thank you, simple and efficient
+1 or more compact mode: grep -xE '.{5}' arguivo.txt | grep -E '(.)\1' | grep -i '[aeiou]'
1
Hello, good afternoon.
I hope that’s what you need :)
#!/bin/bash
vCharsVogal=(aa ee ii oo uu)
vCharsConso=(bb cc dd ff gg hh ii jj kk ll mm nn pp qq rr ss tt vv xx zz ww yy)
vCharVogal=(a e i o u)
for line in $(cat $1); #//$1 eh o parametro para o arquivo de entrada
do
#1 -Primeiro testa se possui 5 chars
if (("${#line}" == "5"));
then
#2 - Depois verifica se possui repeticao de chars vogais
continua=1
for char in ${vCharsVogal[*]}
do
countChar=$(echo "${line}" | awk -F"${char}" '{print NF-1}')
if (("$countChar" >= "1"));
then
#3 - Se entrou aqui, quer dizer que jah possui vogal :)
echo "$line"
continua=0
break
fi
done
#Se nao teve nas vogais, ai faz as consoantes
if(("${continua}" == "1"));
then
for char in ${vCharsConso[*]}
do
countChar=$(echo "${line}" | awk -F"${char}" '{print NF-1}')
if (("$countChar" >= "1"));
then
#3 - Vai verificar se existe vogal
for vogal in ${vCharVogal[*]}
do
countVog=$(echo "${line}" | awk -F"${vogal}" '{print NF-1}')
if (("$countVog" >= "1"));
then
echo "$line"
continua=0
break
fi
done
if(("${continua}" == "0"));
then
break
fi
fi
done
fi
fi
done
thanks, the solution is good tbm although more complex than the @Tom Melo. However your solution will enable me tb other solution.
The code needs to be adapted a little to treat other characters. When I saw the solution of @Tom Melo, I confess that I wanted to remove my hahahha publication. The good thing is that we learn from both sides :) Thanks!
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In general, mathematically regular expressions have no memory, could not know what is behind. This is only possible using some modern meta characters (a little more detail here)
– Jefferson Quesado
Now, it is possible to predict which are all possible cases of repetition, so could put in a large group of "or"s...
– Jefferson Quesado