Scanf inside the printf

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#include <stdio.h>
#include <stdlib.h>

int main()
{
    int i;
    printf("digite um número %d",scanf("%d",&i));

}

The following program only gives the result 1 and I do not understand why.

c

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1 answer

2

Because the Scanf returns an integer with the amount of entries.

scanf("%d",&i)

This will return number 1

scanf("%d" "%d",&p,&i)

Will return the number 2 and so on.

If you put inside a while, as follows:

while ( scanf("%d", &i) == 1)

It will be true. If you put 

while ( scanf ("%d" "%d", &p, &i) == 2)

Will be true also.

And so on and so forth.

  • In C it is correct to concatenate strings separating them with space, now this is not traditional to see. In your example, in reading two integers, I would expect to find "%d %d", nay "%d" "%d". Again, it’s not wrong, it’s just not very usual to find this concatenation in family operations scanf and printf

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