Define function result return or method

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Editing: A previous function generates a list like this: 

['Responsável atual', 'Número do processo', 'Foro de tramitação', 'Data da intimação 05/10/2017', 'Data da ação 15/08/2011']

This is the previous list in "Data". Data is my final report. It contains hundreds of processes listed. I take one by one of these processes, access and ADD the information from "Parties". That is, I INCREMENT this list with complementary information, which are, for example:

['Exequente', 'União', '(CNPJ do exequente)', 'Executado', '(CNPJ fictício) 00.345.123/0001-00', 'Nome da empresa executada']

My role TRAVERSES that list, FINDS the CNPJ (or CPF) target and TREATS that information to determine who will be NEW responsible. So there are several Eps, as he considers the number 3 (just before the bar). If there is 0, 9 or 8 it IGNORES and picks up the previous one (in this case, 2). If there is 0, 9 or 8 ignores and picks up the previous and so on, so it is a bit confusing the criterion of determination of the responsible. In the end, when I have determined who is responsible according to this criterion, I need to add all this new information from that list to that previous list (i.e., I add "Parties" + 'distributefor' to "Data") to complete the report...

#############################

I have a function:

def PegaDadosPartes(dados):
      distribuicaoPara = VerificaDist(partes)
      dados.append(str(distribuicaoPara) + " @")
      for x in range(len(partes)):
          dados.append(partes[x] + '@')
      del partes[0:len(partes)]
      return dados

It takes a data set (list 'parts') from another function, and feeds another list ('data') with this information, BEING THAT the variable 'distributionPara' calls the function 'Verificadist(parts)' to get its value.

This value depends on a number of treatments. Among them, check if in 'parts' there is CNPJ’s or CPF’s, and treat differently case by case, thus:

def VerificaDist(partes):
      posicao = []
      temCnpj = 0
      for x in range(len(partes)):
            verificaOutroCnpj = re.search("\d{2}.\d{3}.\d{3}/\d{4}-\d{2}", partes[x]) 
            if verificaOutroCnpj:
                  posicao.append("CNPJ " + verificaOutroCnpj.group())
                  temCnpj = temCnpj + 1
            verificaCpf = re.search("\d{3}.\d{3}.\d{3}-\d{2}", partes[x]) #Se não achou CNPJ, busca CPF.
            if verificaCpf:
                  posicao.append("CPF " + verificaCpf.group())
      if temCnpj > 0:
            Caso1(posicao) #Primeiro caso: consta CNPJ.
      else:
            Caso2(posicao) #Segundo caso: consta CPF.

In either case, the treatment functions will "slice" the variable, as the treatment criteria are different. In the CNPJ the digit before the "/" determines the responsible one. In the CPF, the eighth digit defines this. The final function does this:

def TrataDistribuicao(alvos): #("Alvos" são as partes "fatiadas" da informação)
      analisa = open('C:\\Regras.txt', 'r') #É o arquivo que contém as regras de designação de responsável, tipo "Se o dígito é 8 responsável fulano, se 7 cicrano" e assim por diante...
      regrasDeDistribuicao = analisa.readlines()
      for x in range(len(regrasDeDistribuicao)):
            regrasDeDistribuicao[x] = regrasDeDistribuicao[x].split(',')
      for x in range(len(regrasDeDistribuicao)):
            if alvos[0] == regrasDeDistribuicao[x][0]:
                  distribuicaoPara = str("Distribuir para " + regrasDeDistribuicao[x][1] )
            elif alvos[1] == regrasDeDistribuicao[x][0]:
                  distribuicaoPara = str("Distribuir para " + regrasDeDistribuicao[x][1])
            elif alvos[2] == regrasDeDistribuicao[x][0]:
                  distribuicaoPara = str("Distribuir para " + regrasDeDistribuicao[x][1] )
            elif alvos[3] == regrasDeDistribuicao[x][0]:
                  distribuicaoPara = str("Distribuir para " + regrasDeDistribuicao[x][1])
analisa.close()

It turns out, at the end of all this, I’m not getting "set" the variable "distributionPara". How to do?

python variables logic method

  • Honestly, I reread your question about 5x and still can’t understand. You have a function, PegaDadosPartes, that receives only one parameter, dados, and this function depends on the return of another function, VerificaDist, you receive as a parameter partes, that does not even belong to the scope; the return of this function is added to dados, but then you iterate on partes, which, again, does not belong to the scope, adding its elements in dados, to finally return dados. It didn’t make sense. I could explain exactly what you are trying to do, because I think that your solution is not feasible.

  • And why in function TrataDistribuicao there are 4 if/elif who do exactly the same thing?

  • I edited the question trying to be clearer. Thank you for your attention!!!

1 answer

0

I added a return distribuicaoPara in each subsequent function, providing all the possibilities of setting the variable, and the value was finally returned! Thank you all.

I also changed the loop. It was like this:

def TrataDistribuicao(alvos):
analisa = open('C:\\Regras.txt', 'r')
regrasDeDistribuicao = analisa.readlines()
for x in range(len(regrasDeDistribuicao)):
    regrasDeDistribuicao[x] = regrasDeDistribuicao[x].split(',')

resultado = None #Acrescentei essa variável para servir de critério pra saída do laço.
for x in range(len(alvos)):
    for y in range(len(regrasDeDistribuicao)):
        if alvos[x] == regrasDeDistribuicao[y][0] and resultado == None:
            resultado = ("Distribuir para " + regrasDeDistribuicao[y][1] + " considerado " + dados[0])

if resultado == None:
    distribuicaoPara = "CNPJ ou CPF não coincidente com nenhuma situação previamente prevista. Verificação manual."
    return distribuicaoPara
else:
    distribuicaoPara = resultado
    return distribuicaoPara
analisa.close()

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