Success message after completing the PHP form

Question

Success message after completing the PHP form

Asked 7 years, 2 months ago

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I’m trying to create a simple form for logging a visit at a location. However, I am unable to place a "Data Successfully Sent" message on the same page of this form. The validation of this form, before sending to the Database, I did in PHP, according to the code below:

form_contact.php

<?php

?>
<!DOCTYPE html>
<html lang="pt-br">
    <head>
        <head>
        <meta charset="utf-8">
        <meta http-equiv="X-UA-Compatible" content="IE=edge">
        <meta name="viewport" content="width=device-width, initial-scale=1">
        <title>contato</title>
        <link href="css/bootstrap.min.css" rel="stylesheet">
    </head>
    <head>
    <body>
            <div class="container">

        <form class="form-horizontal" method="POST" action="salva_mensagem.php">
        <div class="form-group">
                    <label for="inputEmail3" class="col-sm-2 control-label">Nome</label>
                    <div class="col-sm-10">
                        <input type="text" name="nome" class="form-control" placeholder="Nome Completo" required>
                    </div>
                    <label for="inputEmail3" class="col-sm-2 control-label">Email</label>
                                        <div class="col-sm-10">
                        <input type="mail" name="email" class="form-control" placeholder="Seu EMail" required>
                    </div>
          <label for="inputEmail3" class="col-sm-2 control-label">Telefone</label>
          <div class="col-sm-10">
              <input type="text" name="assunto" class="form-control" placeholder="Telefone" required>
          </div>
                    </div>
<div class="form-group">
                    <div class="col-sm-offset-2 col-sm-10">
                        <center><button type="submit" value="Enviar" class="btn btn-success" >Enviar</button></center>
                    </div>
          </div>

    </form>
    </div>
    </body>
</html>

salva_mensagem.php

<?php
    include_once('conexao.php');
    $nome = $_POST['nome'];
    $email = $_POST['email'];
    $assunto = $_POST['assunto'];
    $mensagem = $_POST['mensagem'];

    $result_msg_contato = "INSERT INTO mensagens_contatos(nome, email, assunto, mensagem, created) VALUES ('$nome', '$email', '$assunto', '$mensagem', NOW())";
    $resultado_msg_contato= mysqli_query($conn, $result_msg_contato)

?>

Do not use Code snippet (Stack Snippets) for PHP, read: http://meta.pt.stackoverflow.com/q/2115/3635

– Guilherme Nascimento

2017/10/04 at 18:07

6 answers

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by Luiz Gustavo Costa Ceolin • **271** points · Answer 1 · 2017-10-04T15:16:17+00:00

You can display a successful Alert, I think you can do so

if($resultado_msg_contato->rowcount()<=0){
    echo '<script>alert("Ocorreu um erro!!"); </script>';
}else{
    echo '<script>alert("Dados enviados com sucesso!!"); </script>';
}

by Guilherme Nascimento • **98,651** points · Answer 2 · 2017-10-04T18:24:48+00:00

First of all make a check of the mysqli_query, for this use the mysqli_error($conn):

if ($resultado_msg_contato) {
    //Mensagem de successo
} else {
    //Mensagem de erro com mysqli_error($conn)
}

You can then send the POST pro same address and making use of if and isset, let the action="" empty like this:

<form class="form-horizontal" method="POST" action="">

The whole code should look like this:

<!DOCTYPE html>
<html lang="pt-br">
    <head>
        <head>
        <meta charset="utf-8">
        <meta http-equiv="X-UA-Compatible" content="IE=edge">
        <meta name="viewport" content="width=device-width, initial-scale=1">
        <title>contato</title>
        <link href="css/bootstrap.min.css" rel="stylesheet">
    </head>
    <head>
    <body>
            <div class="container">
    <?php

    if (isset($_POST['nome'], $_POST['email'], $_POST['assunto'], $_POST['mensagem'])) {
        include_once('conexao.php');

        $nome = $_POST['nome'];
        $email = $_POST['email'];
        $assunto = $_POST['assunto'];
        $mensagem = $_POST['mensagem'];

        $result_msg_contato = "INSERT INTO mensagens_contatos(nome, email, assunto, mensagem, created) VALUES ('$nome', '$email', '$assunto', '$mensagem', NOW())";
        $resultado_msg_contato= mysqli_query($conn, $result_msg_contato);

        if ($resultado_msg_contato) {
            echo '<div class="alert alert-success">Dados enviado com Sucesso!</div>';
        } else {
            echo '<div class="alert alert-danger">Erro:', mysqli_error($conn),'</div>';
        }
    }
    ?>
        <form class="form-horizontal" method="POST" action="">
        <div class="form-group">
                    <label for="inputEmail3" class="col-sm-2 control-label">Nome</label>
                    <div class="col-sm-10">
                        <input type="text" name="nome" class="form-control" placeholder="Nome Completo" required>
                    </div>
                    <label for="inputEmail3" class="col-sm-2 control-label">Email</label>
                                        <div class="col-sm-10">
                        <input type="mail" name="email" class="form-control" placeholder="Seu EMail" required>
                    </div>
          <label for="inputEmail3" class="col-sm-2 control-label">Telefone</label>
          <div class="col-sm-10">
              <input type="text" name="assunto" class="form-control" placeholder="Telefone" required>
          </div>
                    </div>
<div class="form-group">
                    <div class="col-sm-offset-2 col-sm-10">
                        <center><button type="submit" value="Enviar" class="btn btn-success" >Enviar</button></center>
                    </div>
          </div>

    </form>
    </div>
    </body>
</html>

Or using Ajax

You can use Ajax (XmlHttpRequest) combined with addEventListener("submit", ...) to send the form and treat the response in the callback:

var oReq = new XMLHttpRequest();

//Defina como true
oReq.open("POST", form.getAttribute("action"), true);

//Função assíncrona que aguarda a resposta
oReq.onreadystatechange = function()
{
    //Se 4 é que concluiu
    if (oReq.readyState === 4) {

        //Checa o status HTTP
        if (oReq.status >= 200 && oReq.status < 300) {
            if (oReq.responseText === "sucesso") {
                alert("Dados enviados com sucesso");
            } else {
                alert("Erro:" + oReq.responseText);
            }
        } else {
            alert("Erro HTTP:" + oReq.status);
        }
    }
};

oReq.send(new FormData(form)); //Envia os campos com a API

The salva_mensagem.php should look like this:

<?php

if (isset($_POST['nome'], $_POST['email'], $_POST['assunto'], $_POST['mensagem'])) {
    include_once('conexao.php');

    $nome = $_POST['nome'];
    $email = $_POST['email'];
    $assunto = $_POST['assunto'];
    $mensagem = $_POST['mensagem'];

    $result_msg_contato = "INSERT INTO mensagens_contatos(nome, email, assunto, mensagem, created) VALUES ('$nome', '$email', '$assunto', '$mensagem', NOW())";
    $resultado_msg_contato= mysqli_query($conn, $result_msg_contato);

    if ($resultado_msg_contato) {
        echo 'sucesso';
    } else {
        echo 'Erro:', mysqli_error($conn);
    }
}
?>

Should stay like this:

<!DOCTYPE html>
<html lang="pt-br">
    <head>
        <head>
        <meta charset="utf-8">
        <meta http-equiv="X-UA-Compatible" content="IE=edge">
        <meta name="viewport" content="width=device-width, initial-scale=1">
        <title>contato</title>
        <link href="css/bootstrap.min.css" rel="stylesheet">
    </head>
    <head>
    <body>
        <div class="container">
        <form id="meuform" class="form-horizontal" method="POST" action="salva_mensagem.php">
        <div class="form-group">
                    <label for="inputEmail3" class="col-sm-2 control-label">Nome</label>
                    <div class="col-sm-10">
                        <input type="text" name="nome" class="form-control" placeholder="Nome Completo" required>
                    </div>
                    <label for="inputEmail3" class="col-sm-2 control-label">Email</label>
                                        <div class="col-sm-10">
                        <input type="mail" name="email" class="form-control" placeholder="Seu EMail" required>
                    </div>
          <label for="inputEmail3" class="col-sm-2 control-label">Telefone</label>
          <div class="col-sm-10">
              <input type="text" name="assunto" class="form-control" placeholder="Telefone" required>
          </div>
                    </div>
<div class="form-group">
                    <div class="col-sm-offset-2 col-sm-10">
                        <center><button type="submit" value="Enviar" class="btn btn-success" >Enviar</button></center>
                    </div>
          </div>
    </form>
    </div>

        <script type="text/javascript">
        function EnviarForm(e) {
            //Previne enviar o Form normal
            e.preventDefault();

            //Pega o form
            var form = e.target;

            //Previne enviar múltiplas vezes até que o Ajax complete
            if (form.enviando) {
                return;
            }

            form.enviando = true;

            var oReq = new XMLHttpRequest();

            //form.getAttribute("action") é para pegar o action do Form
            oReq.open("POST", form.getAttribute("action"), true);

            //Função assíncrona que aguarda a resposta
            oReq.onreadystatechange = function()
            {
                if (oReq.readyState === 4) {

                    //desbloqueia o form
                    form.enviando = false;

                    if (oReq.status >= 200 && oReq.status < 300) {
                        if (oReq.responseText === "sucesso") {
                            alert("Dados enviados com sucesso");
                        } else {
                            alert("Erro:" + oReq.responseText);
                        }
                    } else {
                        alert("Erro HTTP:" + oReq.status);
                    }
                }
            };

            oReq.send(new FormData(form)); //Envia os campos com a API FormData
        }

        document.getElementById("meuform").addEventListener("submit", EnviarForm);
        </script>
    </body>
</html>

by AugustoMorais • **106** points · Answer 3 · 2017-10-04T15:13:47+00:00

You can do as follows,within your PHP, just put.

echo 'Data sent successfully';

Remembering that anything else you will print inside your php on the display screen, just give the echo in the string or variable.

Follow an example of the gringo friends.

https://stackoverflow.com/questions/23877551/how-do-i-return-a-message-after-submitting-a-form-on-my-page-with-php

by user60252 · Answer 4 · 2017-10-04T15:51:09+00:00

The question post a "Data Successfully Sent" on the same page of this form.

just put onSubmit="alert('Dados enviado com Sucesso.');" >

in form

<form class="form-horizontal" method="POST" action="salva_mensagem.php" onSubmit="alert('Dados enviado com Sucesso');">

example

<form class="form-horizontal" method="POST" action="/unanswered/tagged/?tab=newest" onSubmit="alert('Dados enviado com Sucesso');">
        <div class="form-group">
					<label for="inputEmail3" class="col-sm-2 control-label">Nome</label>
					<div class="col-sm-10">
						<input type="text" name="nome" class="form-control" placeholder="Nome Completo" required>
					</div>
                    <label for="inputEmail3" class="col-sm-2 control-label">Email</label>
                                        <div class="col-sm-10">
						<input type="mail" name="email" class="form-control" placeholder="Seu EMail" required>
					</div>
          <label for="inputEmail3" class="col-sm-2 control-label">Telefone</label>
          <div class="col-sm-10">
			  <input type="text" name="assunto" class="form-control" placeholder="Telefone" required>
		  </div>
					</div>
<div class="form-group">
					<div class="col-sm-offset-2 col-sm-10">
						<center><button type="submit" value="Enviar" class="btn btn-success" >Enviar</button></center>
					</div>
		  </div>

	</form>

by I_like_trains • **1,430** points · Answer 5 · 2017-10-04T16:19:41+00:00

You can set a notification balloon with this message!

At the end of php code, refresh the page and send the url &f=1

In the text balloon, add if(isset($_GET['f'])) and target the intended message!

In steps

Create balloon, recommend using bootstrap with position: fixed; right: 10px; bottom:10px; in styles.
Use <meta refresh> or header('Location: link_do_site'); and add &f=1
And finally, before where the div of alert, add if(isset($_GET['f'])){.

This way it will be pleasant to the view and quite practical!

by Mariana Bayonetta • **869** points · Answer 6 · 2017-10-04T18:03:48+00:00

If you put this script on your page, an Alert will appear warning you that you have been saved and then return to the previous page. :)

salva_mensagem.php

<?php

    $nome = $_POST['nome'];
    $email = $_POST['email'];
    $assunto = $_POST['assunto'];
    $mensagem = $_POST['mensagem'];

    $strcon = mysqli_connect('localhost','root','', 'seu_banco') or die('Erro ao conectar ao banco de dados');
    $sql = "INSERT INTO mensagens VALUES ('$nome', '$email', '$assunto', '$mensagem')"; 
    mysqli_query($strcon,$sql) or die("Erro ao tentar cadastrar registro");
    mysqli_close($strcon);

    echo '<script type="text/javascript">
            alert("Salvo com Sucesso !");
            window.history.go(-1);
        </script>';

?>