Problem with Keypressed Event to open another JAVAFX window

Question

My problem is the following, this way that I am opening the window I have a problem about using the Keypressed function.Because this way my method needs the Actionevent parameter that when using the getSource() method, returns me the button and opens the window correctly, but that when I click the button.Then for the button function there to work inside the keyPressed function, I would have to put a parameter there too. I tried to put new Actionevent and(), the error goes away but the source is different when I press enter, which causes the window n to be opened.

Below is the example that opens the second window by clicking on the button. And last the Keypressed event.

Aah, the idea is a login window, then when I give enter do the checks and Talz and open the other window.But only works by clicking even

private void openJanela(Actionevent Event) throws Exception {

    Parent main_tela = FXMLLoader.load(getClass().getResource("FXMLTelaPrincipal.fxml"));
    Scene main = new Scene(main_tela);
    Stage st = (Stage) ((Node) event.getSource()).getScene().getWindow();
    st.hide();
    st.setScene(main);
    st.show();

}

public void initialize(URL url, ResourceBundle rb) {
    btnLogar.addEventHandler(KeyEvent.KEY_PRESSED, (KeyEvent event) -> {
        try {
            if (event.getCode() == KeyCode.ENTER) {
                abrirJanela();
            }
        } catch (Exception ex) {
        }
    });

Answer 1

Javafx has an easier way to make a button react to the ENTER event, just put it default button. Basically a button in Javafx can be 3 types:

• Normal: Default behavior, react only with click;
• Default: A default button is a button that also triggers with a VK_ENTER type keyboard event, provided that no other node on the scene consumes that event;
• Cancel: A cancel button is a button that also triggers with a VK_ESC type keyboard event, provided that no other node on the scene consumes this event;

See the correct way below:

Button mybutton = new Button();
mybutton.setDefaultButton(true);

mybutton.setOnAction((ActionEvent t) -> {
    // Seu evento
});