1
Where to start placing an ordinal numbering on a given byte, I start counting the most significant (the left )or the least significant (the right)?
For example for the decimal number 128 having the represntation in binary:
1000 0000
If I want to refer to eighth byte bit, who is the digit in question?
1 or 0 ?
It would be mode A or mode B?
Mode A
1000 0000
8765 4321
Mode B
1000 0000
1234 5678
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The way To would be right.
Ignore the name bit - A binary value is represented in the same way as a decimal value: In an integer the highest value positions are located on the left, since new positions are added when the previous position suffers overflow:
8 + 1 // 9: Uma casa decimal
9 + 1 // 10: Não pode ser contido em apenas uma posição,
10 // casa decimal 2 recebe o valor em overflow.
...
98 + 1 // 99: Duas casas decimais
99 + 1 // 100: Não pode ser contido em apenas duas posições,
100 // casa decimal 3 recebe o valor em overflow.
Thus:
128 = 100 + 20 + 8
In the above example we can say the position(house) 3 holds the value 1, which means 100 decimally.
In binary the value
1000 0000
Holds the value 1 in position 8, which also means 128 (2 to 7 power).
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I’m not sure I understand what you want, if it’s something conceptual, if it’s concrete. Concretely it’s much more complicated than that. I do not know if the question is not wide. Enumerate how? by the question I can only assume that is look there and count to 8 and get the desired digit.
– Maniero