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I’m a beginner with Spring and would like to use Opensessioninview so I don’t have to implement my Filter.
Filing cabinet web xml.
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>Archetype Created Web Application</display-name>
<!-- openSessionInView SpringMVC -->
<filter>
<filter-name>OpenSessionInViewFilter</filter-name>
<filter-class>org.springframework.orm.hibernate4.support.OpenSessionInViewFilter</filter-class>
<init-param>
<param-name>sessionFactoryBeanName</param-name>
<param-value>sessionFactory</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>OpenSessionInViewFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<!-- FIM openSessionInView SpringMVC -->
<context-param>
<param-name>ApplicationContext</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<servlet>
<servlet-name>PedidosMVC</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>PedidosMVC</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.request.RequestContextListener</listener-class>
</listener>
<session-config>
<session-timeout>10</session-timeout>
</session-config>
<context-param>
<param-name>javax.faces.PROJECT_STAGE</param-name>
<!-- <param-value>Production</param-value> -->
<param-value>Development</param-value>
</context-param>
</web-app>
Filing cabinet Applicationcontext.xml
<!-- Enable autowire -->
<context:annotation-config />
<context:component-scan base-package="com.pedidos" />
<mvc:annotation-driven />
<mvc:resources mapping="/resources/**" location="/resources/" />
<mvc:resources mapping="/webjars/**" location="/webjars/" />
<mvc:resources mapping="/resource/**" location="/resource/theme/" />
<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource">
<property name="driverClassName" value="com.mysql.jdbc.Driver" />
<property name="url" value="jdbc:mysql://localhost:3306/pedidosmvc" />
<property name="username" value="root" />
<property name="password" value="167396052" />
</bean>
<!-- Session Factory Declaration -->
<bean id="sessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="packagesToScan" value="com.pedidos.entities" />
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop>
<prop key="hibernate.show_sql">true</prop>
<prop key="hibernate.enable_lazy_load_no_trans">true</prop>
<prop key="hibernate.default_schema">pedidosmvc</prop>
<prop key="format_sql">true</prop>
<prop key="use_sql_comments">true</prop>
<prop key="hibernate.hbm2ddl.auto">update</prop>
</props>
</property>
</bean>
<tx:annotation-driven transaction-manager="transactionManager" />
<bean id="transactionManager"
class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory" />
</bean>
</beans>
My problem is using fetch=FetchType.LAZY
He presents the following exception
type Exception report
message org.hibernate.Lazyinitializationexception: failed to lazily initialize a Collection of role: com.pedidos.entities.Representante.listUser, no Session or Session was closed
The server encountered an Internal error that prevented it from fulfilling this request.
Exception
org.apache.jasper.JasperException: org.hibernate.LazyInitializationException: failed to lazily initialize a collection of role: com.pedidos.entities.Representante.listUser, no session or session was closed org.apache.Jasper.servlet.Jspservletwrapper.handleJspException(Jspservletwrapper.java:556) org.apache.Jasper.servlet.Jspservletwrapper.service(Jspservletwrapper.java:477) org.apache.Jasper.servlet.Jspservlet.serviceJspFile(Jspservlet.java:395) org.apache.Jasper.servlet.Jspservlet.service(Jspservlet.java:339) javax.servlet.http.HttpServlet.service(Httpservlet.java:731) org.apache.Tomcat.websocket.server.WsFilter.doFilter(Wsfilter.java:52) org.springframework.web.servlet.view.InternalResourceView.renderMergedOutputModel(Internalresourceview.java:168) org.springframework.web.servlet.view.AbstractView.render(Abstractview.java:303) org.springframework.web.servlet.Dispatcherservlet.render(Dispatcherservlet.java:1246) org.springframework.web.servlet.Dispatcherservlet.processDispatchResult(Dispatcherservlet.java:1029) org.springframework.web.servlet.Dispatcherservlet.doDispatch(Dispatcherservlet.java:973) org.springframework.web.servlet.Dispatcherservlet.doService(Dispatcherservlet.java:895) org.springframework.web.servlet.Frameworkservlet.processRequest(Frameworkservlet.java:967) org.springframework.web.servlet.Frameworkservlet.doGet(Frameworkservlet.java:858) javax.servlet.http.HttpServlet.service(Httpservlet.java:624) org.springframework.web.servlet.Frameworkservlet.service(Frameworkservlet.java:843) javax.servlet.http.HttpServlet.service(Httpservlet.java:731) org.apache.Tomcat.websocket.server.WsFilter.doFilter(Wsfilter.java:52) org.springframework.Orm.hibernate4.support.Opensessioninviewfilter.doFilterInternal(Opensessioninviewfilter.java:151) org.springframework.web.filter.Onceperrequestfilter.doFilter(Onceperrequestfilter.java:107)
Thanks for your help.
And what’s the problem? There’s some mistake?
– Woss
Good morning Anderson... I added the exception that is returning. Thank you
– Tulio L.