Error: cannot Convert float* to float

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-1

Error is on the line:

quadrados = (desvio_qualquer * desvio_qualquer);

Error: Cannot Convert Float* to Float

#include <iostream>
#include <string.h>
#include <sstream>
#include <cmath>
using namespace std;
struct leituras{
  float vetor[1000];
  int n;
}n1;
//int quadrados(leituras n1, int i, float desvio_qualquer, float quadrados);
int main ()
{
    int i;
    float soma, media, desvio, desvio_qualquer, soma_dos_desvios_de_leituras,x,quadrados;
    cout << "Programa para calcular a media das leituras de um experimento e o desvio da media, o programa trabalha com no maximo 1000(mil) leituras.\n";
    cout << "Digite o numero de leituras que seram inseridas no programa, sendo inteiro não negativas e diferente de zero e menores ou igual a 1000,e use pontos e não virgulas para expressar numeros decimais :\n";
    cin >> (n1.n);
    if(n1.n != 0) {
        for( i=0; i<n1.n; i++)  {
            cout << "Digite as leituras:\n ";
            cin >> (n1.vetor[i]);
            }
        for( i=0; i<n1.n; i++)  {
            soma = soma+n1.vetor[i];
}
        media=soma/n1.n;
        for( i=0; i<n1.n; i++)  
        {
            desvio_qualquer = n1.vetor[i] - media;
            //quadrados(n1.n, i, desvio_qualquer, quadrados);
            soma_dos_desvios_de_leituras = soma_dos_desvios_de_leituras + pow(desvio_qualquer,2);
    }
        x=pow(n1.n,-1);
        desvio=sqrt(x*soma_dos_desvios_de_leituras);
        cout << "A media é: " << media << " \n E o desvio é: " << desvio << endl;

}
    else {
        cout << "Digite a leitura:\n ";
        cin >> (n1.vetor[1]);
        cout << "A media é: " << n1.vetor[1] << " E o desvio é 0(zero)" << endl;
}


  return 0;
}

//int quadrados(leituras n1, int i, float desvio_qualquer, float *quadrados) {

//  for( i=0; i<n1.n; i++){
//      quadrados = (desvio_qualquer * desvio_qualquer);
//}
//return 0;
//}                                 Não entendi o erro.
c++

1 answer

4

Remember that when you want to change the value of a pointer you should use *

So the line goes like this:

*quadrados = (desvio_qualquer * desvio_qualquer);

In your case you were trying to give a value to the pointer, which represents a memory address.

  • Thanks, but it’s still not working, look please:

  • @user3720765, I have tested and the error no longer occurs. What problem is occurring? Take a look at the code that is here: http://textuploader.com/0bqr and try to create a new project by pasting this code into the main

  • struct readings{ float vector[1000]; int n; }n1; int squares(readings n1, int i, float deviation_any, float *squares); int main() { int i; float sum, media, deviation, deviation_any, soma_dos_deviation_de_readings,x,squares; media=sum/n1.n; for( i=0; i<n1.n; i++) { deviation_any = n1.vector[i] - media; squares(n1.n, i, deviation_any, squares); soma_dos_deviation_de_readings = soma_dos_deviations_readings + squares; Return 0; } int squares(n1, int i, deviation_float any, float *squares){ for( i=0; i<n1.n; i++){ *squares = (deviation_any * deviation_any);

  • now says you can’t use the square function

  • 1

    In this case if your problem "cannot Convert float* to float" has been solved please mark the answer as valid and open a new question so that more people can help you. Remember to add the formatted source code.

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