Problem running tasks with two buttons in the same form in c#

Question

I’m new to c, so forgive me for making a rookie mistake. I need to put two buttons on the same form,one to call a form, and another to perform a function I’m trying like this:

    private void button1_Click(object sender, EventArgs e)
    {

        dados_bd dados_formulario = new dados_bd();
        conection_database conexao = new conection_database();

        dados_formulario.NOME = textBox1.Text;
        dados_formulario.LOCAL_ARMAZENAMENTO = textBox2.Text;
        dados_formulario.DESCRICAO = textBox3.Text;

        conexao.cadastro(dados_formulario);

        textBox1.Text = "";
        textBox2.Text = "";
        textBox3.Text = "";
   }

    private void button2_Click(object sender, EventArgs e)
    {
        Form2 teste = new Form2();
        teste.ShowDialog();
    }

If I put the function of calling another form in button1, it works, but when I set it to button 2, it doesn’t. Even, no function is available to button2. I would like some clarification on this.

---

I changed the code, as suggested above, but it didn’t work. So I put the suggestion in the button1, that it was the only one that worked, and the function that was previously assigned to it, on the button that did not respond.

But, behold, now the two buttons are calling to form2, even if the function is assigned only to the button1:

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;

namespace WindowsFormsApplication1
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }

        private void Form1_Load(object sender, EventArgs e)
        {

        }

        private void label1_Click(object sender, EventArgs e)
        {

        }

        private void button1_Click(object sender, EventArgs e)
        {
            new Form2().Show();

       }

        public void button2_Click(object sender, EventArgs e)
        {
            dados_bd dados_formulario = new dados_bd();
            conection_database conexao = new conection_database();

            dados_formulario.NOME = textBox1.Text;
            dados_formulario.LOCAL_ARMAZENAMENTO = textBox2.Text;
            dados_formulario.DESCRICAO = textBox3.Text;

            conexao.cadastro(dados_formulario);

            textBox1.Text = "";
            textBox2.Text = "";
            textBox3.Text = "";
        }
    }
}

Answer 1

Apparently there’s nothing peculiar that makes the code work on the first button and it doesn’t work on the second. Anyway, I would slightly alter the invocation:

private void button2_Click(object sender, EventArgs e)
{
    new Form2().Show();
}

ShowDialog() is not a good because the form will be invoked as modal, which does not allow to touch other Forms while it’s open.

---

Possibly the two buttons are pointing to the same event in case:

    private void button1_Click(object sender, EventArgs e)
    {
        new Form2().Show();
    }

Click on each button and check the properties, especially in the event part:

Answer 2

Your problem is in the event assignment, you can assign it via code:

 public Form1()
    {
        InitializeComponent();
        button1.Click += button1_Click;
        button2.Click += button2_Click;
    }

    void button2_Click(object sender, EventArgs e)
    {
        //Evento click do botão 2
    }

    void button1_Click(object sender, EventArgs e)
    {
        //Evento click do Botão 1
    }

or by IDE as the Gypsy showed above, would look like this:

remembering that, when giving 2 Clicks on the button (inside the visual studio), it will already be taken to the Click event, or give 2 clicks on the white space in front of the desired Event, in the properties window, which will be generated a new event for control.