reversing a long sequence in c

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reversing a long sequence in c

Asked 7 years, 2 months ago

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I need to invert a sequence of numbers, for example, if 1234 is inserted, I print 4321. The code is working, but for Type 0123 or Type 1230 entries the zero is simply "deleted", but I needed the zero also to be displayed on the screen. I couldn’t think or find a solution to this, someone can help me?

int main()
{
    long n;
    long inverso;

    scanf("%ld",&n);

    do
    {
        inverso=n%10;
        printf("%ld",inverso);
        n/=10;

    }while(n>0);
    printf("\n");
    return 0;
}

n need to be long? 0 the left will always be ignored for long, this is normal. 0123 is the same thing as 123. The same happens with 1230, initially 0 is there, because it is 1.230, after reversing the same happens and it happens to be 321.

– George Wurthmann

2017/04/26 at 18:30
For me, with the ticket 1230 worked perfectly. To 0123, in fact, 0 is ignored for the reason explained above.

– Woss

2017/04/26 at 18:33
yes it needs to be long, this is a lot of URI, number 1984, for those who know the URI...

– soAna

2017/04/26 at 18:34
Statement: https://www.urionlinejudge.com.br/judge/en/problems/view/1984

– Woss

2017/04/26 at 18:48
If you ask as input a number can not have a 0 at the beginning.

– Maniero

2017/04/30 at 14:08

1 answer

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by Anonimo • 91 points · Answer 1 · 2017-04-27T14:02:38+00:00

Use the 0* specifier to specify the size of the field to be printed with zeros on the left. For example for a 5-position field:

printf("%0*lld\n", 5, 123);

In your case you need to determine the size of the field that can be done, for example by printing the original number into a string (sprintf) and using the strlen function of .