Why are you giving him endless noose?

Question

Exercise: Write an algorithm to generate and write a table with s sine values of an angle A in radians, using the series of Truncated Mac-Laurin, presented below:

A3
A5
A7
sen A = A - 6 + 120 - 5040

Conditions: the values of angles A shall vary from 0.0 to 6.3 inclusive from 0.1 in 0.1.

my code :

#include <stdio.h>
#include <math.h>

int main () {

    float A = 0.0, valor_seno;
    float aprs_tela;

    while (A <= 6.3) {
        aprs_tela = A;
        A = A - (((pow(A,3) / 6) + (pow(A,5) / 120)) - (pow(A,7) / 5040));
        valor_seno = sin(A);

        printf("O valor do seno (%.1f) com a série de Mac-Laurin é %.2f\n\n",aprs_tela ,valor_seno);

        A = A + 0.1;
    }

    return 0;
}

Answer 1

At the beginning of the program you put that A = 0.0; (will receive 0).
Then you check whether A is < that 6,3 (Yes, for the first tie that’s true).

Then you run the line:

A = A - (((pow(A,3) / 6) + (pow(A,5) / 120)) - (pow(A,7) / 5040));

It turns out that A is equal to zero, and zero to any number is zero. In short, (((pow(A,3) / 6) + (pow(A,5) / 120)) - (pow(A,7) / 5040)) This all goes to zero.
Then you try to assign A = A - [expressao]; (That is, A (which is zero) will receive the result of the expression, which is also zero.

Then you put:

A = A + 0.1;

blz here you assign a positive value to "A".
Only a diminished value of a higher value, this will always be lower, for example: 0 - 0,1 = -0,1 (That is, the value of A will always be less than 6.3 so it is in an infinite loop).

You can understand?