Print "n" natural odd numbers

Question

I’m solving an exercise that asks me to enter a value for example: 5 and print the first 5 natural odd numbers in the case:

entree:

Enter the value of n: 5

• 1
• 3
• 5
• 7
• 9

The code I wrote works but it does not seem to me the best logic for solving it. Would anyone know any other "simple" solution because I’m still learning

n = int(input("Digite o valor de n: "))

i = 1

while i <= (n+n):
if i % 2 != 0:
    print(i)
    i += 1
else:
    i += 1

Answer 1

A very simple alternative would be with the function range(start, stop, step)

• Start: initial sequence number.
• Stop: up to this number, but does not include it in the sequence.

• Step: difference between each number in the sequence.

  n = int(input("Digite o valor de n: "))
  for i in range(1, n+n, 2):
     print(i)
  

output:

Answer 2

I was able to understand and apply with another logic without having to add n+n, in case it would look this way:

n = int(input("Digite o valor de n: "))

i = 0
ímpar = 1

while i < n: 
  print(ímpar)
  i = i + 1
  ímpar = ímpar + 2

Answer 3

It is also possible to solve the problem without using any iteration loop type, just unpacking the values of the sequence, generated with range(), using the operator * and passing them as arguments to function print().

In the example separator, parameter sep, will be a character newline:

n = int(input("Digite o valor de n: "))
print(*range(1, 2*n, 2), sep="\n")

Upshot:

Digite o valor de n: 5
1
3
5
7
9

Another approach manipulating the arguments of print() can be obtained by combining the function of the odd natural numbers f(x) = 2x + 1 | x N within a list comprehension

n = int(input("Digite o valor de n: "))
print(*[2*x+1 for x in range(n)], sep="\n")

Answer 4

Just to record another alternative (and I admit that maybe it’s a half Overkill, since the other solutions with range are simpler), you can use the module itertools:

from itertools import islice, count

n = int(input("Digite o valor de n: "))
for i in islice(count(1, 2), n):
    print(i)

First, count(1, 2) returns an iterator starting at 1, skipping 2 by 2 (thus, I guarantee it only has odd numbers, and always starting from the 1). Coming up next, islice receives this iterator and picks up the first ones n elements of it.

The result is the first n odd numbers.

Answer 5

I did so in Python, which includes the last number if it is odd.

num = int(input("Digite um número inteiro: "))

for num in range(1, num+1, 2):

    print(num)

Answer 6

To get the 5 first odd numbers:

    n = int(input("Digite o valor de n:"))

    # Inicializações
    i = 0 # Contador
    r = 1 # Resultado

    # Imprima os números ímpares
    while i < n:
       i += 1
       print(r)
       r += 2

Answer 7

You can use the for cycle, which I like very much:

printf("Digite o numero");
int k = scanf(&k);

for(int x = 0; x < k; k++){
if(k%2 != 0){
printf("%i\n", k);
} // end if
} // end for