Regular Expression for password

Question

I’m trying to do a strong javascript password check. Initially I want to check if in the string there is the occurrence of 02 numbers in the following conditions:

1. "12vvv": two consecutive numbers or more of anything returning true
2. "1a1a": two numbers separated or more returning true
3. Must return true in all cases where the text contains 02 numbers or more, regardless of its placement.

I got the expression below that returns true only in case 2 ("1a1a"):

/(\d{1}).(\d{1})/.test("a1a1")

But best option was no regular expression:

  function hasTwoNumber(text) {
    var arr        = text.split(""),
        tamanho    = arr.length,
        qtd = 0;

    for (var i = 0; i < tamanho; i++) {
      if (/[0-9]/.test(arr[i])) {
        qtd++;
      }
    }

    return qtd > 1;
  }

console.log(hasTwoNumber("1a1a")); //true
console.log(hasTwoNumber("11aa")); //true

I would like to get that same result with regular expression. Someone knows a regular expression that meets these conditions?

Answer 1

A different way:

var a = '1a11aa1'.match(/\d.*\d+/g) != null;
console.log(a);

var b = 'a1a11'.match(/\d.*\d+/g) != null;
console.log(b);

var c = '1aaaa1'.match(/\d.*\d+/g) != null;
console.log(c);

var d = 'aaaa1'.match(/\d.*\d+/g) != null;
console.log(d);

Answer 2

You can use the following regex /\d.\d|\d{2}./ she says she should marry a number followed by anything and then another number or (|) two numbers followed by anything.

Examples:

/\d.\d|\d{2}./.test('1bab22') //false, não tem nada depois dos dois números seguidos
/\d.\d|\d{2}./.test('1b1') //true, casa o primeiro padrão (lado esquerdo)
/\d.\d|\d{2}./.test('1baaa') //false
/\d.\d|\d{2}./.test('11') //false
/\d.\d|\d{2}./.test('111') //true, devido ao ponto casar qualquer coisa

If it is necessary to return false for three consecutive numbers exchange the point for \D which means no digit.

/\d\D\d|\d{2}\D/.test('111') //false

Can identify 2 or more numbers with '2aaaa1a'.match(/\d+/g), in which case the approach changes from validate to capture and then check if it matches the expected.

var temNumero = '2aaaa1a'.match(/\d+/g);
if(temNumero.length >=2){
   console.log('válido');
}else{
   console.log('não atende o padrão');
}