Json filter in Angularjs

Question

I would like how I can filter this JSON by COD and bring only the chosen one.
I am bringing the value of the code by the url and would like to filter only to display the name of the chosen option.
NOTE: The user will not enter the value because it was in a list on the previous screen in which he chose.
I am using Angularjs
Example:

{"COD":"15","NOME":"14.01 Histórico Escolar."},
{"COD":"16","NOME":"14.02 Histórico Escolar - Regime de Urgência"}

Then, I would like to filter only through the COD column and bring and present on the screen the NAME.

Answer 1

ANGULAR FILTER

To solve your problem just use the Filters of Angular, the following example:

var app = angular.module('myApp', []);
app.controller('myCtrl', function($scope) {
    $scope.valores =  [
      {
        "COD":"15",
        "NOME":"14.01 Histórico Escolar."
      },
      {
        "COD":"16",
        "NOME":"14.02 Histórico Escolar - Regime de Urgência"
      }];
});

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="myApp" ng-controller="myCtrl">
  <input type="text" placeholder="Buscar por ID" ng-model="filtro.COD">
  <div ng-repeat="x in valores | filter: filtro">{{x.NOME}}</div>
  
</div>

Answer 2

For you to perform the filter the way you pointed can use the same pure javascript

$scope.valores =  [
  {
    "COD":"15",
    "NOME":"14.01 Histórico Escolar."
  },
  {
    "COD":"16",
    "NOME":"14.02 Histórico Escolar - Regime de Urgência"
  }]

$scope.filtrarCodigo(codigo){
   return $scope.valores.filter(function(item){ 
                                    return (item.COD == codigo)
                                });
}