Fulltextsearch in SQL Server

Question

Hello! All right?

I need to make an appointment with fulltextsearch, because it needs to be indexed. However, I am not managing to assemble a query that returns all the possibilities, as if it were a like.

The appointment I was able to assemble is as follows

DECLARE @nmPessoa varchar(250)  

/*Exemplos de consultas*/
-- 1
--SET @nmPessoa = '1ª VARA  DE EXECUÇÃO FISCAL ESTADUAL - CURITIBA'
--2
--SET @nmPessoa = 'Curitiba'
--3
--SET @nmPessoa = 'Curi' 
--4
--SET @nmPessoa = 'FUMPISUL'
--5
--SET @nmPessoa = 'FUM'
--6
--SET @nmPessoa = 'CAMARA GRANDE'
--7
--SET @nmPessoa = 'FUMPISUL - FUNDO MUNICIPAL DE PREVIDÊNCIA DE PIRAÍ DO SUL'

    set @nmPessoa = '"*'+ @nmPessoa +'* "'  

    select p.nmPessoa
    from pessoa p       
    where CONTAINS(p.nmPessoa ,@nmPessoa) 

In the case of the first example, you must return the exact record (this is correct)

In the 2nd example all the records that have 'Curitiba' in the sentence (is correct)

Already in the 3rd example, should bring the phrases that has 'Curi', IE, the records of 'Curitiba' should also appear (It is not working)

And in example 6, it should bring the phrases that have "Camara" and "Grande", but it doesn’t work, it returns the phrases that have 'Camara Grande', as if it were only 1 word.

The consultation using like is this, but I can not use because it takes minutes to return. The amount of records is large.

DECLARE @nmPessoa varchar(250)  
DECLARE @parametro varchar(250) 
set @parametro = REPLACE( LTRIM(RTRIM(@nmPessoa)), ' ', '%')    
    select p.nmPessoa
    from pessoa p           
    where p.nmPessoa LIKE '%'+@parametro+'%'

Thanks for your help.