Syntax error on another machine

Question

I have a machine on which Python 2.6.6 is installed, in a certain part of a script I do the following command:

with open('saida1.txt') as saida:
    for line in saida:
        if "]L" in saida:
            print line

In which I seek the string "]L" in the output file1.txt and print the corresponding line.

Running the same script with the same command on another machine with Python 2.4.3 displays syntax error in the "open command".

Could you tell me if this is because of a version or a compiler or something? Or if there is another way to make the same resource?

Error:

$ python teste.py

 File "teste.py", line 1
    with open('saida1.txt') as saida:
            ^
SyntaxError: invalid syntax

Answer 1

The problem is in context manager (with ...) which does not exist before python 2.5, try the following:

saida = open('file.txt', 'r')
lines = saida.readlines()
for line in lines:
    if "]L" in saida:
        print line
saida.close()

Or in order to cover possible exceptions:

fout = None
try:
    fout = open("tests.txt", "r")
    lines = fout.readlines()
    # fazer o que petendes 
finally:
    if fout is not None:
        fout.close()

Answer 2

Good morning, I’m not from are python, but I googled it and I found this:

open isn't missing in 2.4. What's missing is the with statement (added in Python 2.5 as PEP-0343)

To do the same code without with:

fout = open("text.new", "wt")
# code working with fout file fout.close() Note the fout.close() is implicit when using with, but you need to add it yourself without

The open was only introduced in version 2.5+ Try using the code above, and a searched on the open 2.4;

Syntaxerror: invalid syntax on "with open" on python-2.4.3

What is the Alternative for open in python 2.4.3