5
Guys I have a URL as follows "test/#/app/product/2" and I wanted to take this number at the end of the URL and use it to make a condition as I do to bring this ID?
5
Guys I have a URL as follows "test/#/app/product/2" and I wanted to take this number at the end of the URL and use it to make a condition as I do to bring this ID?
3
Assuming that this 2 has been defined as a route variable
.state('produtoView', {
url: '/produto/:id' ...
You can redeem this variable id
by injecting the $stateParams
in your controller and taking the value of the route variable by its name $stateParams.id
.
Take a look at the documentation of ui-router, below it speaks of a new way of fetching the variable in the new versions of ui-router, then the $stateParams
is depreciated.
I didn’t put it the new way because I didn’t know this fact either.
3
Use the service $location
.
For example, for a given URL http://example.com/#/some/path?foo=bar&baz=xoxo
:
var abUl = $location.absUrl(); // => "http://example.com/#/some/path?foo=bar&baz=xoxo"
var url = $location.url(); // => "/some/path?foo=bar&baz=xoxo"
var prot = $location.protocol(); // => "http"
var host = $location.host(); // => "example.com"
var path = $location.path(); // => "/some/path"
var srch = $location.search(); // => {foo: 'bar', baz: 'xoxo'}
In your specific case, $Location.path() will return /app/produto/2
.
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You’re wearing
ngRoute
orui-router
to create routes with variables?– Giovane
I use the ui-router
– Alfredo Lima