Chained list in C-add!

Question

I am in doubt in an exercise and if anyone could help me would be very good! Thanks from now!

#include <stdio.h>
#include <stdlib.h>

struct Numeros {
    int numero;
    struct Numeros *next;
};

void adicionar (int n, struct Numeros **here) {
    struct Numeros *temporario;

    if((*here)->next == NULL)
       {getch();
       (*here)->numero=n;
       }
       else if(((*here)->next->numero!=n)&&((*here)->next->numero>n))
       {
           temporario=(struct Numeros*)malloc(sizeof(struct Numeros));
           temporario=(*here)->next;
           temporario->numero=n;
           temporario->next=(*here)->next;
           (*here)->next=temporario;
           free(temporario);
           }
}

void remover (int n, struct Numeros **here) {
// 1- Verificar se não existem elementos na lista
// 1.1- sair

// 2- Caso exista elementos, verificar se o atual éo que se deseja remover
// 2.1- atualizar os ponteiros

// 3- Caso não seja o elemento procurado, avançar na lista procurando!
}

void imprimir (struct Numeros *here) {
    printf("[%d]", here->numero);
    if (here->next != NULL) 
        {
        imprimir(here->next); // manda imprimir o proximo!
        }
}

 int main (){
struct Numeros *head = NULL;

int flag = 0, numero;
do {
    printf("1) adicionar\n");
    printf("2) remover\n");
    printf("3) imprimir\n");
    printf("0) sair\n");
    printf("Informe uma opcao: ");
    scanf("%d", &flag);

    switch(flag){
        case 0: // sair
            break;
        case 1: // adicionar
            printf("--------------------------------------------\n");
            printf("Informe o valor para ser adicionado: ");
            scanf("%d", &numero);
            adicionar(numero, &head);
            printf("--------------------------------------------\n");
            break;
        case 2: // remover
            printf("--------------------------------------------\n");
            printf("Informe o valor para ser removido: ");
            scanf("%d", &numero);
            remover(numero, &head);
            printf("--------------------------------------------\n");
            break;
        case 3: // imprimir
            printf("--------------------------------------------\n");
            (head != NULL) ? imprimir(head) : printf("Não existem elementos na lista\n");;
            printf("\n");
            printf("--------------------------------------------\n");
            break;
        default:
            printf("Opcao invalida\n");
    }

} while (flag);

free(head);

return 0;
}

In relation to

void remover(int n,struct Numeros **here)

do not need to worry because I have not yet started to develop or do, so I would like to have the opportunity to try, but my doubt is in adding, already from the

if((*here)->next == NULL)

begins to have flaws in the program. If someone can explain to me what is wrong and what is missing it would help me a lot in understanding. Thanks!!!

Answer 1

Try to use:

(*(*here)).next == NULL

Instead of using:

(*here)->next == NULL