Run PHP without updating the entire page

Question

Run PHP without updating the entire page

Asked 7 years, 11 months ago

Viewed 2,398 times

3

My code is this:

<?php
$buscarusuario=$pdo->prepare("SELECT * FROM top5 WHERE status = 'ativo' ORDER BY colocacao ASC");
$buscarusuario->execute();

// Exibir com Fetch_Obj
$linha=$buscarusuario->fetchAll(PDO::FETCH_OBJ);
foreach ($linha as $listar) {

?>

<!-- INÍCIO TOP -->

  <div class="col-md-12 wow fadeInLeft" data-wow-duration="1000ms" data-wow-delay="300ms">
    <div id="top5-caixa">
      <div class="colocacao">
      <?php echo $listar->colocacao; ?>
      </div>
      <div class="musica-cantor">
        <p class="cantor"><?php echo $listar->cantor; ?></p>
        <p class="musica"><?php echo $listar->titulo; ?></p>
      </div>
      <div class="like">
        <a href='extra/likes.php?id=<?php echo "".$listar->id.""; ?>' alt="Gostei"><img src="images/like.png" height="40px" width="40px" id="like"></a>
      </div>

    </div>
  </div><!-- ./ COL-MD-12 -->
<?php } ?>
</div><!-- ./ ROW -->
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Inserir dados PDO</title>
</head>
<body>
<?php
// Incluindo arquivo de conexão
include("conexao.php");
$pdo = conectar();
// Recuperando valores
$id = $_GET['id'];

// Realizando consulta
$atualizartop=$pdo->prepare("UPDATE top5 SET likes = likes +1 WHERE ID='$id'");
$atualizartop->bindValue(":id",$id);
$atualizartop->execute();
if($atualizartop->rowCount() > 0):
    echo "Obrigado por votar!";
else:
    echo "Desculpe, mas ocorreu algum erro.";
endif;

?>

</body>
</html>

I wonder if clicking on the link to vote would return a "Thank you for voting!" without having to upgrade to the page that has the php function.

If anyone knows how to help, thank you.

To return this message, you must be sure that the recording was correct. For this, you have to have the script of the recording at the beginning of the program, not at the end, where you receive a message and in a div receive that message.

– William Aparecido Brandino

2016/08/02 at 18:10

1 answer

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by leandroungari • **840** points · Answer 1 · 2016-08-02T18:16:48+00:00

Put a id in your image with the value like. In an extension file .js, goes that code:

$("#like").click(function(){
//evento de click sobre a imagem

    var id = $(this).attr('id'); //aqui você pegao valor do atributo id
    $dados['id'] = id; //esse array será passado para o php só que por POST ao invés de GET

    $.ajax({

        url: "incrementaLike.php", //Aqui vai o nome do seu arquivo PHP
        type: "post",
        async: true,
        data: $dados,
        cache: false
     })
     .done(function(data){

        //neste o ponto, o código php já foi executado e voltou para aqui se tudo ocorreu sem erro
        console.log(data);
     })
    .fail(function(){

        //vem para cá se algum erro ocorreu
        console.log("Deu alguma errada no php");
    });
});

You should separate your PHP into a separate file and the path to it goes in the attribute url.

In case I put a file called incrementaLike.php in the same folder as your html and also the archives js.

incrementaLike.php

<?php

include("conexao.php");
$pdo = conectar();
// Recuperando valores
$id = $_POST['id'];

// Realizando consulta
$atualizartop=$pdo->prepare("UPDATE top5 SET likes = likes +1 WHERE ID='$id'");
$atualizartop->bindValue(":id",$id);
$atualizartop->execute();
if($atualizartop->rowCount() > 0):
    echo "Obrigado por votar!";
else:
    echo "Desculpe, mas ocorreu algum erro.";
endif;

?>