1
I have a question. I’m doing a job where I have a page that shows the name of a club.
while($exibe = mysql_fetch_array($qr)){
echo '<p><h2>'.$exibe['Nome'].'</h2></p>';
}
And I want you to click the name or a button in front to show me all the information of this club on another page.
while($exibe = mysql_fetch_array($qr)){
echo'<div id="tabs-1">
<img align="right" src="logos/'.$exibe["Nome"].'.jpg">
<p>Nome:<b>'.$exibe["Nome"].'</b></p>
<p>Morada: '.$exibe["Morada"].'</p>
<p>Distrito: '.$exibe["Distrito"].'</p>
<p>Concelho: '.$exibe["Concelho"].'</p>
Just so I understand what you want, something like that would be enough?
– Erlon Charles
I want the data to appear in the second while. For example: I click on the name "A" and then show me the data I chose in the second page
– ChrisAdler