Can this asterisk pyramid code be further simplified?

Question

I have a simple exercise where I need to do an asterisk pyramide using repeating structure.

The pyramid has 17 columns and 9 rows.

My program displays it correctly, It is possible to reduce some line or some for?

#include <stdio.h>
#include <conio.h>


main()


{
    int l,c,e;


    for (l = 1; l <= 10; l = l + 1)
    {
        for(e=1; e<=(l-1);e = e + 1)
        {
            printf(" ");
        }
        for (c = 1; c <= 10-l; c = c + 1)
        {
            printf("*");
        }

        for (c = 2; c <= 10-l; c = c + 1)
        {
            printf("*");
        }
    printf("\n");
    }
getch;
}

Answer 1

An alternative:

#include <stdio.h>
int main() {
    int l, c;
    for (l=1; l<10; l++) {
        for(c=0; c<=7+l; c++)
            printf(c<9-l?" ":"*");
        printf("\n");
    }
}

See working on IDEONE.

Answer 2

Does it give:

#include <stdio.h>

int main() {
    for (int x = 9; x > 0; x--) {
        for(int y = 9 - x; y > 0; y--) printf(" ");
        for (int y = 1; y <= x * 2 - 1; y++) printf("*");
        printf("\n");
    }
}

Behold working in the ideone. And in the repl it.. Also put on the Github for future reference.

In addition to eliminating one of the ties that only repeated what the other did, I gave an organized and modernized in the code. I preferred to invert the loop count and use easier to read variable name.

Do not use conio.h. Is obsolete.

But if you want to make it simpler and use a loop, you can do this:

int main(void) {
    for (int x = 0; x < 1; x++) {
        printf("*****************\n");
        printf(" ***************\n");
        printf("  *************\n");
        printf("   ***********\n");
        printf("    *********\n");
        printf("     *******\n");
        printf("      *****\n");
        printf("       ***\n");
        printf("        *\n");
    }
}

When less deviations and variables and changes of state, simpler, even if it is not the shortest.

If you still want the shortest you have a few tricks possible. An option:

#include <stdio.h>
int main(void) { for (int x = 9; x > 0; x--) printf("%.*s%.*s\n", 9 - x, "         ", x * 2 - 1, "*****************"); }

Behold working in the ideone. And in the repl it.. Also put on the Github for future reference.