1
Within a function I have a cumulative variable, and I call this function over and over again, the problem that it loses values every time it enters. Summing up what I want to do is:
def teste(a):
a=a+1
c=7
print a
return c
def main():
a=1
for b in range(0,5):
c=teste(a)
main()
the exit is:
would like to maintain the value of a, and the output in that case be increased.
3
Python does not have a method of declaring static variables, but there are some means and do this.
def static_num(): # método com variável estática
static_num.x += 1 # incremento
return static_num.x
static_num.x = 0 # inicia variável
if __name__ == '__main__':
for i in range(10):
print static_num()
0
Then the error that must, is due to the fact that you are just calling the variable that is in the test function. Without incrementing any value to it, then it will repeat in the lop for. To solve this just add the variable b that is in your for:
def teste(a):
a=a+1
c=7
print (a)
return c
def main():
a=1
for b in range(0,5):
c=teste(a+b)
main()
So it will increase with the variable without mutalá directly.
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You are with two
as in your code: one is the formal parameter of the function and the other is the global variable.– Pablo Almeida
this is a simple code to reproduce the idea, in case if it were global it would work, think that the second part is within a function
– Joannis