Doubt average with Python 3.5

Question

I am creating a program, using Python 3.5, to calculate average, but in my school there are some subjects with two teachers, and each one gives a different test.

The problem is that the code I created averages (Prova 1 + Prova 2)/2, which is equal to media1, (Atividade 1 + Atividade 2)/2, which is equal to average 2, and the final average is with Simulated (media1+media2+simulado)/3, and when it’s a matter I don’t put anything on P2 it’s a mistake. I was thinking, when the user enters the matter name run such code, and another name, another code, how do I do this?

My code:

nota1 = float(input("Nota1: "))

nota2 = float(input('Nota 2: '))

simulado = float(input('Nota simulado: '))

ac1 = float(input('Nota AC1: '))

ac2 = float(input('Nota AC2: '))


media1 = (nota1+nota2)/2
mediaAC = (ac1+ac2)/2
mediaf = (media1+simulado+mediaAC)/3 

print (mediaf)

if mediaf == 6:
   print("na media")


if mediaf < 6:
   print("abaixo da media")

Answer 1

from functools import partial

notas = list(map(float,list(iter(partial(input, 'Nota: '), ''))))
ac = list(map(float,list(iter(partial(input, 'AC: '), ''))))
simulado = float(input('Nota simulado: '))

media_notas = sum(notas)/len(notas)
media_ac = sum(ac)/len(ac)
media_final = (media_notas + media_ac + simulado) / 3 


print('medias: ', media_notas, media_ac, media_final)

if media_final >= 6:
    print('na media')
else:
    print('abaixo da media')

This way you type as many notes as necessary, until the note value is empty (type 'Enter'). Example:

$ python notas.py 
Nota: 5
Nota: 10
Nota: 
AC: 5
AC: 5
AC: 
Nota simulado: 10
notas:  7.5 5.0 7.5
na media

Answer 2

Oops! Dude, I’m a beginner but I tried to implement a solution for you:

qtd_notas = int(input("Digite a quantidade de notas: "))
notas = 0
for i in range(0, qtd_notas):
    notas += input("Digite a nota " + str(i + 1) + ": ")

media = notas / qtd_notas

simulado = input("Nota Simulado: ")

acs = 0

for i in range(0, qtd_notas):
    acs += input("Notas AC" + str(i + 1) + ": ")

media_ac = acs/qtd_notas

media_final = (media + simulado + media_ac) / 3

print (media_final)

if media_final == 6:
    print ("na media")
if media_final < 6:
    print ("abaixo da media")

What I did was put in to, at the beginning, the user type the amount of notes that will compose the averages. Ignore the variables.

I hope I’ve helped.

Answer 3

Another way to resolve the issue is as follows:

notas = list(map(float, input('Digite as notas das provas: ').split()))
ac = list(map(float, input('Digite as notas das atividades: ').split()))
simulado = float(input('Digite a nota do simulado: '))

media_provas = (sum(notas) / len(notas))
media_ac = (sum(ac) / len(ac))
media_final = ((media_provas + media_ac + simulado) / 3)

print(f'\033[32mA Média Final é: {media_final:.1f}')

if media_final >= 6:
    print('Na média!')
else:
    print('Abaixo da média')

When we run the algorithm we receive the following message: Digite a nota das provas:. Right now we must type all the notes of evidence, in the same line, separated for a single space and press enter. Then we received the following message Digite as notas das atividades:. Right now we must type all the notes of the activities, in the same line, separated for a single space and press enter. Then we received the following message: Digite a nota do simulado:. At this point we must type the simulated note and press enter.

After you have inserted all the notes the algorithm will perform the calculation of the averages, displaying only the média final and the situação student’s.

Answer 4

Here’s what I did, all right.

     pn=float(input('Digite sua primeira nota: '))

     sn=float(input('Digite sua segunda nota: '))

     m=(pn+sn)/2

     if m<6.00:
         print('Você não passou com {} de média'.format(m))
     if m>=6.00:
         print('Você passou com {} de média'.format(m))