0
I’m not able to display the first 5 divisibles by 3, I put a counter variable, but it returns another number.
#include <stdio.h>
#include <stdlib.h>
int main()
{
int n = 20;
for(int i=1; i<=n; i++) {
if(i%3 == 0)
printf("%d\n", i);
}
return 0;
}
Could someone explain to me how?
3
To display the first 5 numbers just count the number divisible by 3, when the quantity is equal to 5 ends the loop, see the example:
#include <stdio.h>
int main(void)
{
int cont = 0, numero = 0;
while (1)
{
numero++;
if (numero % 3 == 0)
{
printf("%d\n", numero);
cont++;
}
if (cont == 5)
break;
}
return 0;
}
Exit:
3
6
9
12
15
I understood how to do.
1
You need to use a flag to verify that you have printed all the first 5 numbers.
#include <stdio.h>
#include <stdlib.h>
int main()
{
int n = 20;
int flag = 0;
for(int i=1; i<=n; i++) {
if(i%3 == 0) {
flag++;
printf("%d\n", i);
if(flag == 5)
return 0;
}
}
return 0;
}
I’ve tried it this way, and it doesn’t work.
You tried wrong, I just ran this program and it worked.
Yes, it worked now, the order is wrong.
Just one comment, Renato, that has nothing to do with your solution - in general we call (and give the name of) "flag"" to variables that contain a meaning of "true" or "false". In this case, the variable keeps a count, so the best would be a name like "counter".
Browser other questions tagged c algorithm operators flow-control
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Is displaying the numbers
3 6 9 12 15 18, you want to show only the3 6 9 12 15?– gato
Yes, that’s right. the first 5.
– user41646
Opa- take the opportunity to see in the answers the indentation styles of the code. It is much important to correctly indent all lines - helps you and others to read your own code much easier.
– jsbueno