Error from "expected Expression before ːint'"

Question

I was following this example, but it was done on Windows, so it was used <conio.h>. When I try to run on Linux I get 2 errors: an *h=int(tempo);, that I don’t understand why, and the other in the getch. How can I replace them?

#include <stdio.h>

void horario(float tempo, int *h, int *m)
{
    *h=int(tempo);
    *m=(tempo-*h)*60;
}

int main ()
{
    int hora,minuto;
    char resp;
    float t;

    do
    {
        printf("Digite o horario na forma centesimal: ");
        scanf("%f",&t);
        horario(t,&hora,&minuto);
        printf("Horario: %02d:02%d\n",hora,minuto);
        printf("Quer calcular outro horario? (S/N):");
        resp=getch();
    } while (resp=='S');
    getch();
    return 0;
}

Answer 1

To make a "cast" use the desired type between parentheses followed by the value

(int)tempo // cast de tempo para tipo int: correcto
int(tempo) // incorrecto: aparenta ser a chamada da funcao int com argumento tempo

---

You can replace the getch() for getchar() (prototype in <stdio.h> that you’ve already included).

Answer 2

You had two problems:

1. Typecast badly done.

2. getchar instead of getch

   void horario(float tempo, int *h, int *m){
       *h=(int)tempo;
       *m=(tempo-*h)*60;
   }
   
   int main(){
       int hora,minuto;
       char resp;
       float t;
       do
       {
           printf("Digite o horario na forma centesimal: ");
           scanf("%f",&t);
           horario(t,&hora,&minuto);
           printf("Horario: %02d:02%d\n",hora,minuto);
           printf("Quer calcular outro horario? (S/N):");
           getchar();
           resp = getchar();
       } while (resp=='S');
       getchar();
       return 0;
   }