Copy all before the first blank line

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I have a file with several text blocks, separated by blank line. Ex.:

block1
block1

block2

block3
block3

I need a solution with sed, awk or perl that locates the first blank line and redirects the previous block to another file and so on until the end of the file.

I have this sed command that locates the first block, but not the rest: sed -and '/. /! Q'

Can someone help me?

linux shell-script perl awk

2 answers

2

The following command creates files "output1", "output2", etc., with each block. 

awk -v RS="" '{print > "output" NR }' input.txt

Explanation:

  • RS="" records separated by one or more blank lines
  • print > "output" NR writes the block in output+register number.

This is what you want?

  • Exactly John, this is what I needed. Thank you.

0

I’m not sure if I understand correctly, but if your goal is to remove the blank lines, you can use the following command:

sed '/^\s*$/d'

  • Renato, I need to locate the blank line and move everything that comes before it to another file, don’t delete it.

  • Only from the first block? Or VC wants to integrate by the file and generate multiple files ?

  • I need to generate several acquisitions, one for each existing block in the base file.

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