How to check if a value is present within an array?

Question

$idofdb = "25";

$myArray = array();
foreach ( $fthi as $codigo ) {
    $myArray[] = $codigo['ImoCodigo'];
}

$checkValues = array_values($myArray);
$checkString = implode(',', $checkValues); // 3,4,5,6,7,8,9,10,11,12,13,18,19,14,15,2

I’d like to know how to compare $idofdb with $checkString to find out if $idofdb is registered in the database. As we can observe, the output of $checkString is a string of numbers separated by commas.

Answer 1

You don’t need all this, just use the function in_array() right in the array original:

in_array("25", $fthi)

Or if you think you should do something else for some reason:

in_array("25", $checkValues)

Behold working in the ideone. And in the repl it.. Also put on the Github for future reference.

Answer 2

Instead of you turning an array into a string with separate numbers with comma you can use the function in_array:

<?php

$os = array("Mac", "NT", "Irix", "Linux"); 
if (in_array("Irix", $os)) { 
    echo "Tem Irix";
}
if (in_array("mac", $os)) { 
    echo "Tem mac";
}

?>

Look at the Phpfiddle showing the execution.

Answer 3

As friends said, it is not necessary all this. But if still you want to check in string, you can use the strpos

$pos = strpos($checkString, $idofdb);

if($pos == false) {
    echo 'Não tem cadastrado';
}else{
    echo 'A string foi encontrada na db';
}