How to get the current file name

Question

I recently had a problem identifying the current page.

Was using __FILE__ to get the current file, and used substr() to retrieve the string after the last occurrence bar, it turns out that in some operating systems these bars work differently and end up not returning the name in the expected way.

Is there any function/variable that already returns the file name ?

What I currently wear:

 echo substr(__FILE__, strrpos(__FILE__, '\\') + 1, -4);

Used to use:

 echo substr($_SERVER['REQUEST_URI'], strrpos($_SERVER['REQUEST_URI'], '/') + 1, -4);

I just learned:

 echo basename($_SERVER['PHP_SELF'],'.php');

Answer 1

I think the simplest thing is this:

<?php
   basename( __FILE__ );
?>

Alternative, which gives even more information:

<?php
   $path_parts = pathinfo( __FILE__ );
   echo $path_parts['basename'];
?>

See both working on IDEONE.

Answer 2

Just a little observation: There are two ways to get the file name.

Ex. A.php file

<?php
   $dir1 = basename($_SERVER['PHP_SELF']);
   $dir2 = basename( __FILE__ );
        echo "<br><br>Dir 1: ".$dir1;
        echo "<br><br>Dir 2: ".$dir2;
?>

B.php file

<? php inlude('A.php'); ?>

When "compiling" the B.php file, the final result will be:
Dir 1: B.php
Dir 2: A.php

Conclusion: One prints the location of the file being imported and the other prints the file being executed.

;)

Answer 3

You can use the DIRECTORY_SEPARATOR constant to correctly detect which bar is used by your operating system for directory separation.

As a curiosity, there are other constants, such as PATH_SEPARATOR (which stores the character responsible for separating the directories from the path - in windows is ';' and in linux ':') and PHP_EOL, which stores the line break of your operating system.

The code below is multi-platform:

<?php
$file =  substr(strrchr(__FILE__, DIRECTORY_SEPARATOR), 1);
echo $file;

Reference: http://php.net/manual/en/dir.constants.php

Answer 4

The combination explode() & end() can get the same result(take the current file name);

The explode() transforms the string returned by __FILE__ in an array, the delimite is the directory bar that can be \ or / and end() returns the last element of the array that is the file name.

<?php
  $arquivo = explode(DIRECTORY_SEPARATOR, __FILE__);
  echo end($arquivo);

Answer 5

I transform the string constant FILE in an array using the directory separator ( according to operating system - DIRECTORY_SEPARATOR ) as the field separator to create the array. The last element of this array is the file name and its extension.

Examples:

<?php

    $foo = explode(DIRECTORY_SEPARATOR, __FILE__);

    // o ultimo elemento deste array é o nome do arquivo
    $arquivo = end($foo);
?>

The same reasoning can be used to get the file extension

<?php

    $foo = explode('.', __FILE__);

    // o último elemento do arranjo
    $extensao = end($foo);
?>

Extra: getting the single path (path) to the file

<?php

    // caminho para o arquivo
    $caminho = realpath(dirname(__FILE__));
?>