How to transform a mathematical expression into a C language

Question

How can I turn it into C language?

Answer 1

The M function, which you place, is a real function of two real variables, defined by glue (the expression used to compute M(MP,ML) depends on the MP and ML values).

For a real function, of two real variables, a C function that models such a mathematical function can have as a signature float nome_da_funcao(float arg1, float arg2), where arg1 and arg2 are the function variables (in your case, MP and ML).

Depending on the desired accuracy (number of decimal places after the comma or, in C, after the point), it might be necessary to use double, but in this particular case, it seems that float is of good size.

As it is defined by collage, the expression to return its calculated value in (MP, ML) (or, if you like matematiqués, the image of (MP, ML)) depends on a conditional expression applied to the MP and ML arguments. Well, if the expression used to calculate the function value, at the point (MP, ML), depends on whether MP and ML satisfy a certain condition, it is clear that you will need to use in your code a conditional, at least, or more than one, when applicable.

In the case of their function:

if (PM < 5 or ML < 5)

M = Min{MP, ML}<br>

but

M = (7*MP + 3*ML)/10

If you have a function Min(float x, float y) available, your code can be

float M(float MP, float ML)
{
    if((MP < 5.0)||(ML < 5.0))
        return Min(MP, ML)
    else
        return ((7*MP + 3*ML)/10);
}

However, if you don’t have Min(float x, float y), can use

float M(float MP, float ML)
{
    if((MP < 5.0)||(ML < 5.0))
    {
        if (MP <= ML)
            return MP;
        else
            return ML;
    }
    else
        return ((7*MP + 3*ML)/10);
}

or define

float Min(float x, float y)
{
    if (x <= y)
        return x;
    else
        return y;
}

and, together with this function, use the first code.

Answer 2

The whole program goes like this:

 #include <stdio.h>
 int main(){
    double mp, ml;
    printf("Digite o Mp: ");
    scanf("%d",&mp);
    printf("\nDigite o Ml: ");
    scanf("%d",&ml);
    while(mp<5 || ml<5){
        printf("\nMp ou Ml menor que 5,0. Digite o numero novamente");
        printf("Digite o Mp: ");
        scanf("%d",&mp);
        printf("\nDigite o Ml: ");
        scanf("%d",&ml);
    }
    int m;
    //função:
    m=(7*mp+3*ml)/10;
    printf("%d", m);
}