Doubt about decrement operator

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I have these 2 lines in my function, but what would be the line below?

$idade--;

Only Return wouldn’t be the same?

$idade--;
return $idade;

I just wanted to understand what this line would be for. I don’t like to use something I don’t know what it’s for.

Complete code

php

2 answers

5


Only Return wouldn’t be the same?

Not!!!

The $idade-- subtract 1 of the value of $idade. Amounts to:

$idade = $idade - 1;

Therefore, if you withdraw the $idade--, the value returned by its function will always be 1 more than she returns today.

If you want, you can even do both things on the same line, but then you’d need to use --$idade instead of $idade--:

return --$idade;

That’s because the -- at the end first returns the (current) value of the variable, and then decrees. At the beginning it first decrees and then returns. The same is true for increment operators ++ (at the beginning or at the end).

  • $idade = $idade -1, without the m, nay?

  • @Caiofelipepereira Ops, thanks, I hadn’t seen.

  • Dispose. That’s what we’re there for

  • 1

    I get the job now, Thank

  • 1

    Every year it adds up +1, $age-- makes it -1 if the month has not passed and etc.

4

Assuming $idade is a whole, $idade-- is equal to $idade = $idade - 1, as well as $idade++ is $idade = $idade + 1.

This is a decrease operator. See more on manual of PHP

  • 2

    I tried to get something in the manual, but without knowing the name is difficult, thank you.

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