For x in range(y) does not return right

Question

I have a problem with a def x() in python. the problem is "inside" it. Even if I put it right, it returns Isis, no matter.

I’ve tried everything but I can’t figure out why he doesn’t return right.

Here comes the code.

def filters(a, b, c):
    for a in range(1, 1):
    d = "video"
    else:
    d = ""

    for b in range(1, 1):
    e = "&lclk=short"
    else:
    e = ""

    for c in range(1, 1):
    f = "&lclk=hd"
    else:
    f = ""

    i = ("&filters=%s%s%s" % (e, d, f))
    return i

Even if I put Filters(1, 1, 1) it returns only the "elses". Why will it be? Ah detail that if I try to if inside def it speaks "syntax error" :/ ( is python 2.7 )

Answer 1

He will always enter the else because you don’t have any break.

The Else for for for works as follows, if the condition you want is satisfied, leave with the break, otherwise it will perform the else, whereas the for did not meet your expectations.

In addition, I believe that the else, in that case, be unnecessary, since you only want to repeat an assignment once...

What it looks like you want are ifs and not Fors, I’ll put the code I imagine you want:

def filters(a, b, c):
   if a in range(1, 2):
        d = "video"
   else:
        d = ""

   if b in range(1, 2):
        e = "&lclk=short"
   else:
        e = ""

   if c in range(1, 2):
        f = "&lclk=hd"
   else:
        f = ""

   i = ("&filters=%s%s%s" % (e, d, f))
   return i

I imagine that’s what you want to do. In case you just want a fixed value (and not a list, as in the case of range), replace by the following code:

def filters(a, b, c):
   if a == 1:
        d = "video"
   else:
        d = ""

   if b == 1:
        e = "&lclk=short"
   else:
        e = ""

   if c == 1:
        f = "&lclk=hd"
   else:
        f = ""

   i = ("&filters=%s%s%s" % (e, d, f))
   return i