Use a foreach with multiplication between 8-square numbers after the comma + 100 hours

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I’m trying to set up a foreach or something similar to make the following happen:

I hold a value where the same is a fraction of 1, in case it would be 0.00000100 that is, eight houses after the point. I also have a date, for example yesterday’s date 23/04/2015 12:30:12.

What I’d like to do is multiply the fraction (ex: 0.00000150 * 3 = 0.00000450) and at the date add 100 hours.

An example of how it would look, being the base value in 0.00000100 - dia 23/04/2015 14:38:45, where it will be multiplied by 3, something like:

$multiplicado = 3;
$string = '0.00000100 - dia 24/04/2015 12:24:45';

Where the result would be a list more or less like this:

0.00000200 - dia 28/04/2015 16:24:45
0.00000300 - dia 02/05/2015 20:24:48
0.00000400 - dia 07/05/2015 00:25:14

It would be a list more or less like this, where it takes the value and multiplies the fraction by the same and sum 100 hours. It’s take what I got today 0.00000100 and show what I’ll have from here 100 hours, 200 hours and 300 hours. Of course I put multiplied by 3, but it can be more or it can be less.

I do not know if a foreach would be ideal, but I believe that yes... I’m just not able to do it.

If anyone has any idea how to put this together, I’d appreciate it. Thank you

php

  • Multiplying fractions is not a good idea Leander. Decimal numbers are treated as floats and are not exact representations. Prefer to use an integer value, and convert to seconds, for example.

  • Okay, multiply a given fraction by 3, and add 100 hours to a date. However you missed to clarify the most important, this operation must be executed until when? X times? Until another given date? This is the most important part to determine how the loop will be.

1 answer

3

Adapt your idea with the functions dateand strtotime

<?php

    echo date('d/m/Y H:i:s', strtotime('+100 hours', strtotime('24-04-2015 12:24:45')));

  • Hello Jhonatan, thank you so much for your help my friend, forgive me for the delay. That’s almost right, at least the line this straight with what I’m looking for, however I’m not able to mount it within a foreach, as I said... for example, change only a 3 or a 4 so that the same present 3 or 4 times. But thank you very much for your help

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