Why doesn’t my code print?

Question

I wonder why this code I’m creating doesn’t print anything when I compile it:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main (void)

{
    int dadoacerto, vidadrizzt, vidaartemis, dadod, dadoa, CAd = 8, CAa = 5, dadoataqdr, dadoataart;

    scanf("%d\n%d\n%d", &dadoacerto, &vidadrizzt, &vidaartemis);

    srand( (unsigned)time(NULL) );

    dadod = rand() % dadoacerto;
    dadoa = rand() % dadoacerto;

    if(dadod>dadoa)
    {
        dadoataqdr = rand() % 8;//Drizzt ataca primeiro

        if( dadoataqdr>CAa)
        {
            vidaartemis = vidaartemis - dadoataqdr;
            printf("Drizzt %d", dadoataqdr);        
        }
    }   
    else if(dadoa>dadod)
    {
        dadoataart = rand() % 5 + rand() % 5;

        if(dadoataart>CAd)
        {
            vidadrizzt = vidadrizzt - dadoataart;
            printf("Artemis %d", dadoataart);
        }
    }
    else if (dadoa==dadod)
    {
        dadoataqdr = rand() % 8;//Drizzt ataca primeiro

    if( dadoataqdr>CAa)
        {
            vidaartemis = vidaartemis - dadoataqdr;
            printf("Drizzt %d", dadoataqdr);        
        }
    }

return 0;
}

Answer 1

Your program has some logic errors. I ran it here and found, I think, the main problem why your program isn’t printing out a output. The following occurs when your program enters an if, for example the first, it will still have to test to enter the internal if the condition is false the code with the printf will not run and the program will not be able to execute nor another command within an Else, so it will not print anything at the end. As I did not understand very well which purpose of this program becomes a little difficult to tidy up, but you just need to take a little but beware of the if-esle logic.

A possible suggestion would be for you to combine the two conditions into one if only using the operator &&.