Input listing cakephp query result

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Hello, I’m trying to list a result of a query of my controller in an input, but it is returning zero, but when I give print_r, it returns me all array, what’s wrong?

Controller:

public function add() {
    if ($this->request->is('post')) {
        if ($this->Foto->save($this->request->data)) {
            $this->Session->setFlash('Recipe Saved!');
            $this->render('add');
        }
    }
    $acomodacoes = $this->Navigation->find('list');
    $this->set('acomodacoes',$acomodacoes);
    print_r($acomodacoes); // estou dando esse print_r só para ver se realmente existe um array
}

My form:

<?= $this->Form->create('Galeria.Foto',array('type' => 'file')); ?>
<fieldset>            
    <legend><?= __('Adicionar Galeria de fotos'); ?></legend>
     <strong> Hot? </strong>
    <?=  $this->Form->checkbox('hot', array('value' => 1)); ?>
    <?=  $this->Form->input('acomodacoes',array('class' => 'form-control')); ?>
    <?=  $this->Form->input('titulo',array('class' => 'form-control')); ?>
    <?=  $this->Form->input('descricao',array('class' => 'form-control')); ?>                
    <?=  $this->Form->input('Imagem', array('type' => 'file')); ?>

</fieldset>
<?php echo $this->Form->end(__('Submit',array('class' => 'form-control'))); ?>
cakephp

1 answer

1

It is necessary to inform the array $accommodating in the input related. And being several options, you need the property type and options:

$this->Form->input('acomodacoes', array(
    'class' => 'form-control',
    'type' => 'select',
    'options' => $acomodacoes)
);

For the options, you will have as value the id item, and case your Model has defined the displayField, will be this the displayed text.

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