Check that all sub-rray items are in "false" status

Question

I have an array(parent) and within it I have two more arrays. The child arrays exist a property status. I would like to know how I can validate that all items in the array are with the property status as false.

let materials = [
  {
    group: 'A',
    data: [
      { id: 1, name: 'PC Dell', materialGroup: 'A', amount: 1, status: false },
      { id: 2, name: 'Mouse', materialGroup: 'A', amount: 2, status: false }
    ]
  },
  {
    group: 'B',
    data: [
      { id: 3, name: 'Teclado', materialGroup: 'B', amount: 1, status: false }
    ]
  }
];

Answer 1

The method Array.prototype.every checks whether all elements of an array satisfy a predicate. See the example:

const arr1 = [11, 12, 13, 14, 15];
const test1 = arr1.every((num) => num > 10); // verifica se cada elemento é maior que 10
console.log(test1); //=> true

const arr2 = [9, 12, 13, 14, 15];
const test2 = arr2.every((num) => num > 10); // verifica se cada elemento é maior que 10
console.log(test2); //=> false

So you can use this method.

Just note that, as you have a data set with "depth" of two arrays, you will have to nest two calls to every. Sort of like this:

const materials = [
  {
    group: 'A',
    data: [
      { id: 1, name: 'PC Dell', materialGroup: 'A', amount: 1, status: false },
      { id: 2, name: 'Mouse', materialGroup: 'A', amount: 2, status: false }
    ]
  },
  {
    group: 'B',
    data: [
      { id: 3, name: 'Teclado', materialGroup: 'B', amount: 1, status: false }
    ]
  }
];

const result = materials.every((material) =>
  material.data.every((entry) => !entry.status)
);
console.log(result);

---

Not much to do with the question, but notice:

• every checks if the predicate is true for all the array elements.
• some checks if the predicate is true for at least one of the array elements.