Fibonacci-Python

Question

Construct a function, that is, an algorithm that receive the maximum number of the sequence of Fibonacci.

Returning all numbers from zero to zero Fibonacci number less than or equal to the number informed. Example:

Function - fibonacci(10)

Will return - 0,1,1,2,3,5,8

print (" Trabalho de Fibonacci ")

n =int( input(" Digite Quantos termos você deseja :"))
t1 = 0
t2 = 1

print("{} . {} .".format(t1,t2), end="")

cont = 6

while cont <= n:
    t3 = t1 + t2
    print ("  {}.".format(t3),end="")
    t1 = t2
    t2 = t3
    cont +=1

print( " Fim ")  

The code gives an error, I tried to change the cont for 3 but it didn’t work.

Answer 1

Instead of using the variable cont to set the number of repetitions, use the variable itself t3, since she will be responsible for receiving the numbers from the Fibonacci sequence. Thus:

print (" Trabalho de Fibonacci ")

n =int( input(" Digite Quantos termos você deseja :"))
t1 = 0
t2 = 1
t3 = 0

while t3 <= n:
    print("{}.".format(t3), end="")
    t3 = t1 + t2
    t1 = t2
    t2 = t3

print( " Fim ")

I hope I helped, hug.

Answer 2

n = int(input('A sequência de Fibonacci de: '))
a, b = 0, 1
while a < n:
    print(a, end=',')
    a, b = b, a+b
print('FIM')

Answer 3

I believe that way I can help you:

n =int( input(" Digite um teto para a sequência de Fibonacci :"))
t1 = 1
t2 = 0
t3 = 0
t4 = []

while t1 <= n:
    t4.append(t1)
    t3 = t1 + t2
    t2 = t1
    t1 = t3

print(t4)

Answer 4

My code really works.

num = int(input())
def fibonacci(n):
    t1 = 0
    t2 = 1
    t3 = 0
    for _ in range(0, n):
        print(t1)
        t3 = t1 + t2
        t1 = t2
        t2 = t3
fibonacci(num)

Answer 5

lista = ['1', '1']
for contador in range(2,int(input('Digite a quantidade de elementos da série fibonacci que deseja exibir:'))):
    lista.append(int(lista[len(lista) - 2]) + int(lista[len(lista) - 1]))
print(lista)

Answer 6

x = input(int("Digite um inteiro positivo"))
a = 1; b = i = 0
print(f"Estes são os primeiros {x} termos da série de Fibonacci:")
print('\u26C4'*10)
while i < x:
    c = a + b
    a = b
    b = c
    i += 1
    print(a)
phi = a