Split columns without Pandas tab

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Is there any pandas method for splitting columns without separator? would be a kind of excel ext.text.

I have a base with a 20-character column, but I only need the interval between 11 and 14.

ex. 22222222222ABXF22222

Obs. there is no pattern between the kernel I need.

pandas split columns

  • Increment your question with ways you’ve tried to solve your problem

2 answers

1


Two options:

Use str and square brackets:

df['new'] = df['col'].str[11:15]

Or str.Slice:

df['new'] = df['col'].str.slice(11, 15)

Example

>>> import pandas as pd
>>> df = pd.DataFrame({"col": ["22222222222ABXF22222", "33333333333BCYG33333"]})
>>> df
                    col
0  22222222222ABXF22222
1  33333333333BCYG33333

>>> df['new'] = df['col'].str[11:15]
>>> df
                    col   new
0  22222222222ABXF22222  ABXF
1  33333333333BCYG33333  BCYG
>>>

Note: you can assign the result to the column itself ("col") and overwrite what you had previously

I hope it helps

  • Thank you very much! was spectacular!

  • @Eduardogarciadeoliveira, if you think pertinent, mark the answer as a solution and give an upvote. Take the opportunity to read this post

  • 1

    I tried, but as I am new the site returns that was computed, but does not appear as green arrow.

0

Using what the honourable Member said above, we can also simplify and put another way to exclude these unwanted numbers,

IN

>>> import pandas as pd
>>> df = pd.DataFrame({"col": ["22222222222ABXF22222", "33333333333BCYG33333"]})
>>> df['col'].replace(regex=True,inplace=True,to_replace=r'2|3',value=r'')
>>> df

OUT

col
0   ABXF
1   BCYG

Inside the TO_REPLACE you can pass several parameters and in VALUE you will be able to choose what to replace in place of the variable you are taking.

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