Range of values to compare

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When I ask for a random value on Math.Random() I want him to say whether it was normal, disaster or failure, but I can’t get him to talk normal because I need him to say when he’s over 2 and under 19 he failed. Needs to be roll1 > 2 and < 19.

if (roll1 == 2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19){
    console.log(`FALHOU`);
  }
  if (roll1 == 20){
    console.log(`NORMAL`);
  }
  if (roll1 == 1){
    console.log(`DESASTRE`);
  }
}
javascript if operators

  • You should use comparison operators x < y and x > y, or if you want it to be from 2 until 19 use the x >= y and x <= y in IF, the first IF could be if (roll1 >= 2 && roll1 <= 19){, using && to check that both conditions are correct.

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1 answer

2

Test which is easier first, which is unique value, so do this with 1 and 20, then what’s within that range is what’s left, you don’t need to test explicitly, it’s the exception, so it already falls into else if it is not any of the numbers you have tested differently.

And take care that all conditions are bound, the else if serves for this, the execution will fall only on one of the if or else, is a selection of the most suitable, the first one he enters nor tries others, the else alone ensures that you will enter there if you do not enter any if previous. He is like a else if (true).

You need to make sure you can’t give it another value, I imagine not, since the code indicated that.

var roll1 = 3;
if (roll1 == 1) {
    console.log(`DESASTRE`);
} else if (roll1 == 20) {
    console.log(`NORMAL`);
} else {
    console.log(`FALHOU`);
}

I put in the Github for future reference.

If you can have other values then you have to change:

var roll1 = 3;
if (roll1 == 1) {
    console.log(`DESASTRE`);
} else if (roll1 == 20) {
    console.log(`NORMAL`);
} else if (roll1 > 1 && roll1 < 20) {
    console.log(`FALHOU`);
} else {
    console.log(`Deu número inválido`);
}

I put in the Github for future reference.

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