Sum function returns zero

Question

By the time the input is all ok with the information, but in the output only gives the result 0 and do not know what else to do, already I moved and I reworked the whole code.

The idea is that in a array size 6, the internal sum of these elements occurs. In this case the elements are {1,2,3,4,10,11}.

int simpleArraySum(int ar_count, int ar [6]) {
ar_count = 0;
ar [0]= 1 ;
ar [1]= 2;
ar [2]= 3;
ar [3]= 4;
ar [4]= 10;
ar [5]= 11;
int i ;
int result;

for (i=0; i<6; i++){
    ar_count += ar[i];

};

result = ar_count;

return 0;
}

Answer 1

This code is confusing and makes no sense. If you do the simple, doing only what is necessary according to the statement, giving more meaningful names to the variables is easier. Nor was it returning a obtained value, it only returned 0, you can’t expect a different result when the code clearly does this. Start s sum, accumulate (and not counting) and return the result, that’s all:

#include <stdio.h>

int simpleArraySum(int array[6]) {
    int soma = 0;
    for (int i = 0; i < 6; i++) soma += array[i];
    return soma;
}

int main(void) {
    printf("%d", simpleArraySum((int[]){1, 2, 3, 4, 10, 11}));
}

Behold working in the ideone. And in the repl it.. Also put on the Github for future reference.