Fução to find and remove term in the array does not work with variavél!

Question

implementing in my project the user solution Augusto Vasques in the matter :

How to remove an array from occurrence found within a sub array!

I came across the situation of not being able to search for values stored in variables, only works by inserting strings directly! Follows code.

$arr_val=array('abacaxi','limão');

// array para ser modificado
$frutas = [
  ['maça', 1256],
  ['abacaxi', 1234],
  ['pera', 235],
  ['laranja', 2135],
  ['limão', 2315],
  ['morango', 2351]
];

//laço para testar cada valor do array "$arr_val" e remover

foreach($arr_val as $val_busca){
  $frutas = array_filter($frutas, function ($item){
// aqui o valor de cada fruta a ser encontrado "$val_busca" não funciona por variavél
    return !in_array($val_busca, $item);
  });
}

echo "<pre>";print_r($frutas);echo"</pre>";

I thank you all.

Answer 1

You need to bring the variable $val_busca within the scope of the function, or else you will not be able to access it:

foreach($arr_val as $val_busca){
  $frutas = array_filter($frutas, function ($item) use ($val_busca) {
    return !in_array($val_busca, $item);
  });
}

This type of treatment is usually required in languages that manage memory with ARC, as is the case with PHP, because if the function does not run synchronously, the memory space of this variable could be released before its callback function can use it.