How can I split a string by semicolon and take the value of each position after the while?

Question

How can I make one split of a string per semicolon and take the value of each position after the while ?

Example:

result[0] //casa result[1] //carro

My code:

char str[] ="test;car;bar;mouse";
        char * pch;

        string result;

        pch = strtok (str,";");
        while (pch != NULL)
        {

          result += pch;
          printf ("%s\n",pch);
          pch = strtok (NULL, ";");
        }



     printf("value by position 0\n", result[0]);

Answer 1

Can declare a multi char array result[5][10] where there are 5 lines of strings that can have a maximum length of 10 characters in each line. This is a very siples example, can also dynamically make the memory allocation, do char** result and realloc\ malloc as it needs more space.

Here’s an example of how you could solve your problem:

char str[] ="test;car;bar;mouse";
char * pch;
pch = strtok (str,";");
char result[5][10];//declara multi array com 5 linhas e 10 caracteres maximo por linha
int i=0;
while (pch != NULL)
{
     strcpy(result[i++], pch);// a cada linha envia a String pch para result
     printf ("%s\n",pch);
     pch = strtok (NULL, ";");
}

printf("value by position 0 %s\n", result[0]);

Answer 2

This code is not C++, it’s C, if you think you’re learning C++, you’re wrong, just because it compiles in C++ doesn’t mean it’s C++. If you want to do in C++ you have the option here which is much safer because the library already provides adequate mechanisms:

#include <sstream>
#include <iostream>
#include <vector>

using namespace std;

int main() {
    vector<string> strings;
    istringstream texto("test;car;bar;mouse");
    string token;    
    while (getline(texto, token, ';')) {
        cout << token << endl;
        strings.push_back(token);
    }
    cout << "value by position 0 " << strings[0];
}

Behold working in the ideone. And in the repl it.. Also put on the Github for future reference.