PHP - doubts with date("Y-m-d")

Question

Good afternoon person, someone could assist me in a doubt. I have this foreach that traverses an array and checks if the CURRENT DATE is equal to $value['Account']['data_expiration'] If it is he forwards an SMS informing that the account will expire.

foreach ($contasVencida as $key => $value) {
if (date("Y-m-d") == $value['Conta']['data_vencimento'] && !isset($_COOKIE['send_sms_Vayron'])){

    //Faz envio do SMS
    echo $this->element('NexmoMessage');

My doubt would be I would like to not warn the person on the day AND YES the day before or date("Y-m-d") -1 Day

In other words, you would have to take -1day from $value['Account']['expiration date'] because then I would do if the current date equals the maturity account -1Day

so that the SMS firing occurs one day before the account expires. account expires 19/03 the text triggered on 18/03

Answer 1

Use strtotime:

date("Y-m-d", strtotime('+1 day', strtotime($date_raw)))

You can use the same logic (only with -1 day) to subtract from the due date instead of adding the current date.

Answer 2

The way you’re doing it isn’t ideal. With each loop a new date is generated, however, as you are only working with day, month and year, hardly the last date will be different from the first (only if you run the script a few milliseconds before turning day). It is better to create the date before and always use the same variable

For this you can use the API Datetime, objects created from it have the method sub which makes it possible to reduce the date by a certain period, in this case the Perudium of 1 (one) Dia ('P1D'). Then just use the method format to return a string with the specified format

<?php

$date = new DateTime();

$date->sub(new DateInterval('P1D'));

$date = $date->format('Y-m-d');

foreach ($contasVencida as $key => $value) {
    if ($date == $value['Conta']['data_vencimento'] && !isset($_COOKIE['send_sms_Vayron'])){
        //Faz envio do SMS
        echo $this->element('NexmoMessage');

        // ...