How to check if a string contains a word

Question

I wanted to know how to verify if a string exists a word, for example, I have two conditions for a situation the professional string can contain Medico or Paisanamedico. I wanted a north or way to check if the string "professional" contains "Pasaina", below an example of what I imagined

local profissao = GetUserJob(user)
if profissao has "Paisana" then
 print("funcionario fora de serviço")
else
 print("funcionario em servico")
end

Answer 1

Look, you can put your sentence in a variable to check it later...

let profissao = 'Meu texto aqui contém paisana';

then Voce creates a variable for response, together checking the word with .includes

let result = profissao.includes('paisana');

includes this checking if there is the word 'paisana' within the professional variable

let profissao = 'Meu texto aqui contém paisana';
let result = profissao.includes('paisana');

console.log(result);

then just check if the answer is true or false.

if (profissao)
   //codigo

it returns (true), the word plainclothes exists within the professional variable.

to change the status, just update the professional variable that does not contain the word paisana. I hope to have helped.

Answer 2

you can use the.find string from a look at the examples in the documentation

prop = "teste.com.br"

if string.find(prop, "teste") then
    print ("teste está presente na PROP")
else
    print ("test NÃO foi encontrado na prop")
end

the find method returns a Boolean

https://www.gammon.com.au/scripts/doc.php?lua=string.find

have you use string.gmatch to find some part of the string

string.gmatch(str, 'teste')

he gives a split in the string

https://pgl.yoyo.org/luai/i/string.gmatch