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Well, I’m doing this code that’s meant to add and print recursively.
The variable le is the amount of times I want, which would be an accountant to at the end inform the sum of the numbers written and z a parameter to finish recursion. Only at the end print None.
Could someone help me, explain why this happened.
def soma(le,q=0,z=1):
h = float(input("Numero:"))
if le > z:
return soma(le, q+h, z+1)
def main():
q = soma(4)
print(q)
main()
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Its recursive function has only one criterion, which is when le > z, when this check is not true, your function should return the final result.
From what I understand of your code, h is the current value read, q is the accumulator and z is the recursive call counter.
Place return q + h at the end of its function:
def soma(le,q=0,z=1):
h = float(input("Numero:"))
if le > z:
return soma(le,q+h,z+1)
return q + h
I didn’t pay attention to that part!! I think I did!! I will continue practicing similar exercises. Thank you for your attention and help!
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