"List" remains null after using Python append

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I would like to understand why t2 is null after assignment of t1+append.

t1=[1,2]
t2=t1.append(3)
print(t2)
python
  • 1

    .append age in the list, and retorn None, the correct ai, would be just, t1.append(3); print(t1)

2 answers

2


The append() method has no return, it simply does the action of adding a new item to the list. Therefore, when you try to "printar" a return of append, it returns None.

You can do it like this to work:

t1=[1,2]
t2=t1
t2.append(3)
print(t2)

1

Hi, append is sticking a new element (can be a new list) to a current list. To add 3 at the end of the list the command is:

t1=[1,2]
t1.append(3)
print(t1)

Now if you want to append one list to the other first you need to declare the other, then it would be

t1=[1,2]
t2=[3,4]
t1.append(t2)
print(t1)

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