Traversing array of objects

Question

Good night.

I have an array of an object and would like to take two values:

object(OrgaosJurisdicionais)[17]
  protected 'data' => 
    array (size=3)
      'id' => string '3' (length=1)
      'nome' => string 'Tribunal de Justiça do Estado do Pernambuco' (length=44)
      'sigla' => string 'TJPE' (length=4)
  protected 'vdata' => null
  protected 'attributes' => 
    array (size=2)
      0 => string 'nome' (length=4)
      1 => string 'sigla' (length=5)

How do I only get the ID and NAME of this array?

I used the foreach below but did not return any value:

foreach ($unidades as $keys => $unidade)
        {
            echo $keys.' - '.$unidade->nome;
        }

Answer 1

I believe your variable unidades is an array of objects Orgaosjurisditional, this object has an attribute named data and is an array that contains the data id and nome, then to get the id value for example, you have to access the date attribute and then the id key.

<?php
foreach ($unidades as $keys => $unidade) {
    echo $unidade->data['id'] . ' - ' . $unidade->data['nome'];
}

Answer 2

You can extract all values with array_map

$valores[] = array_map(function($obj) {
    return array($obj->data['id'], $obj->data['name']);
}, $unidades);

Answer 3

I was able to resolve it simply with:

echo $unidade->id.' - '.$unidade->nome.'<br>';            

instead of

echo $keys.' - '.$unidade->nome;

being like this:

foreach ($unidades as $keys=>$unidade)
{
    echo $unidade->id.' - '.$unidade->nome.'<br>';
}