Think of it this way:
Alternative A: 1 point
Alternative B: 20 points
Alternative C: 300 points
Alternative D: 4000 points
If a person answers the same alternative up to 10 times, the score will never repeat itself to the value of any of the other alternatives. Example: If the score is 4982, the person answered 2 A, 4 B, 3 C and 1 D. An algorithm for this would be to divide by the highest value of weight and take the rest to go making 3 more divisions, and each value of the division will give the amount of each alternative. I don’t know if you can take the rest, if you can’t, you’d have to subtract the higher weight value from the score by counting how many subtractions are possible before the result is negative or zero. Then I would take the second highest score and so on, until I reached the lowest score value and the subtraction ended at zero.
Please, those who are negative say why. Thank you!
– Cleiton
I want to see if I understand the problem... Is your score due to your limitations? If I could just count the answers on how many were of type A, B, C or D it would have the same effect?
– ewerton
Exactly! The problem is that the tool does not let. So I wanted to know if there is any mathematical joke that could classify
– Cleiton