Calculate average with final exam if I fail standard grades

Question

1. Read the values of four bimonthly school grades of a student represented by the variables N1,N2,N3,N4. Calculate the arithmetic mean (variable MD1) of that student and display the message "Approved with average' if the average obtained is greater than 7.0; otherwise the program must request the fifth exam grade, represented by NE) and calculate a new, variable (MD2) average between the exam grade and the first average. If the average value is greater than or equal to 5, display the message "Approved with average"; otherwise display the message "Disapproved with average". Display the average value next to each message.

Here was the solution I found:

# mudei as variaveis e a quantidade de notas, mas a essencia é a mesma. do que foi pedido.

a = float(input('Nota 1: '))
b = float(input('Nota 2: '))
c = float(input('nota 3: '))
m1 = (a + b) / 2
if m1 >= 7:
    print('Aprovado media %f' % m1)
else:
    m2 = (m1 + c) / 2
    if m2 >= 5:
        print('Aluno aprovado media %f' % m2)
    else:
        if m2 < 4:
            print('Reprovado media %f' % m2)
enter = input('\nPressione <ENTER> para encerrar...')

Such a solution would be satisfactory?

Answer 1

Right away it’s not right because the exercise calls for 4 notes and you only ask for 3 and divide by 2 I don’t know why (I don’t know what better to expect doing this wrong, if it saves typing some characters, only caused confusion)then begins to do something completely meaningless and that is not what the statement asks (must ask for another note). Variable names don’t really matter much.

I think the formula to catch the new average can’t use the old average dividing by 2 because it passes give more weight to the new note, but it’s what the statement asks, so come on.

I did not worry about a possible typo that would break the application, the correct thing is to treat it.

a = float(input('Nota 1: '))
b = float(input('Nota 2: '))
c = float(input('nota 3: '))
d = float(input('nota 4: '))
m1 = (a + b + c + d) / 4
if m1 >= 7:
    print('Aprovado media %f' % m1)
else:
    e = float(input('nota exame: '))
    m2 = (m1 + e) / 2
    if m2 >= 5:
        print('Aluno aprovado media %f' % m2)
    else:
        print('Reprovado media %f' % m2)

Behold working in the ideone. And in the repl it.. Also put on the Github for future reference.