Python sort list of dictionaries by key and value in separate orders

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How to sort a list of dictionaries for example:

nomes = [{'nome': 'joao', 'sobrenome' 'alves'},{'nome': 'joao', 'sobrenome' 'silva'}]
  • In alphabetical order the names
  • In reverse order, surnames that is: in the normal sense the name and in the reverse sense the surname
python python-3.x list classification dictionary

  • You want a way out like: João Alves, João Silva ?

  • João Silva, João Alves. In this case there is only one type of name, but I wanted the tiebreaker to be in the reverse order of the surname, or the opposite of the alphabetical order

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In python the sort of a list is guaranteed stable, that is, in the case of equal comparisons the initial order of the elements is preserved.

Possession of this information makes the problem simple. First it is ordered reversally by the surname, then it is ordered directly by the name.

The following is an example of code implementation:

nomes = [{'nome': 'marcelo', 'sobrenome': 'alves'},
        {'nome': 'joao', 'sobrenome': 'tavares'},
        {'nome': 'joao', 'sobrenome': 'alves'},
        {'nome': 'joao', 'sobrenome': 'nogueira'},
        {'nome': 'joao', 'sobrenome': 'silva'},
        {'nome': 'barbara', 'sobrenome': 'wilson'},
        {'nome': 'antonio', 'sobrenome': 'silva'}]

nomes.sort(key = lambda i: i['sobrenome'], reverse = True)
nomes.sort(key = lambda i: i['nome'])

[print("{:10} {:10}".format(item['nome'], item['sobrenome'])) for item in nomes]

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